Plus jets weigh a lot less at arrival than at departure.
Plus jets weigh a lot less at arrival than at departure.
This caused that place in the runway to suffer severe fatigue damage.
This feels like an essential pattern of the universe or something…
Otherwise you'd have to seriously limit what systems you call "monorail".
The moment you have to build rail-like things you lose most of the cost advantages.
I suspect the ocean in its various states provides quite a bit of dispersion. Replacing deck plates on a ship is a normal part of maintenance. I find it very hard to believe they'd induce randomness rather than having just that one plate get a different hardness (I know some people will screech about that but trust me, the warship industry is well practiced at such things).
And the entire point of the system is to counter the dispersion the ocean provides, much like a Naval Aviator is already required to in order to trap successfully. You are literally flying through a very narrow window that is moving in three dimensions.
Maybe they use plentiful jagged interlocking sharp granite as the base l? (like railroad track foundation)
Next time you're at SFO, SJC, or any other major hub sitting in the plane before it backs out of the gate take a second to gaze upon and admire how pristine all the concrete pads are, it's really impressive.
The concrete they use is very precisely mixed to a specification and then it’s tested for adherence to the spec.
A runway is also going to be 3-4x thicker than a 4-6” thick driveway slab. Probably they also use fiberglass or PVC coated rebar instead of plain steel rebar.
Definitely not an expert here but I can read a civil site plan and hire civil site work subcontractors frequently.
Here’s some information on concrete testing: https://www.concrete.org/frequentlyaskedquestions.aspx?faqid...
Also, Grady is one of the best creators on YouTube, I can’t help but watch his full videos whenever they pop up. I always learn something, even if I’m familiar with the subject.
Edit: Granite is not one of the listed materials in Part 4 - Base Courses of the FAA runway construction guide, here’s the entire thing for reference - https://www.faa.gov/airports/engineering/construction_standa...
There are many ways concrete is superior to pavers. One of the most important is that it is miserable and almost impossible to properly clear snow and ice from pavers.
Ruts were visible pretty quickly again
Some of these klinker roads see heavy traffic and they're perfectly fine. It's also nice to see the automated machines they have for laying them.
Granted private driveways don't need to be absolutely perfect, but if you want it to last for a really long time you need deeper base layers.
The color scales aren't equivalent here but you can see the difference:
Europe - pretty much only unpopulated northern Scandinavia + up in the Alps/Pyrenees getting over 64 days, most of the most densely populated areas with lots of infrastructure below 32 days: https://www.atlas.impact2c.eu/en/climate/freeze-thaw-days/?p...
US - https://www.semanticscholar.org/paper/Climatology-of-Freeze-... (Fig 4.2) - Probably more than 50% is over 75 cycles, and large chunks breaking 100 cycles a year (almost all of New England and some other scattered patches, the Rockies/interior West/Western Plains).
Let's look at just the downward forces:
I need some quick figures 1 - an early Boeing 747: 330 tonnes (metric) fully loaded and 160 tonnes empty. A tonne is 1000 Kg.
According to 2: 240 feet per minute vertical is a hard landing which about 1.2m/s. 60 - 180 is considered ideal, so let's go for about 150fpm which is about 0.7m/s.
We have to estimate the maximum downward force on take off. At the point of just before lift off, the plane has rotated to say, let's say 45 degrees, and its engines are delivering enough force and its wings are delivering enough force to push it into the air. Surely at take off, that vertical force is simply the weight of the aircraft, which has remained the same all the time. It doesn't suddenly push down harder than its weight, that's just what it feels like for a passenger.
So let's allow our jet to be empty on landing and also let the acceleration due to gravity be 10m/s/s
So what is the instantaneous downward force of a mass of 160 tonnes dropping at 0.7 m/s compared to a dead weight load of 330 tonnes. Both are in a gravitational field of 10 m/s/s (or m^s-2).
Now this is where I get a bit lost because force = mass x acceleration and the landing plane is descending at a constant velocity of 0.7 m/s. Mind you, the ascending plane is also ... ascending, or will do but it does not have an instantaneous upward velocity so at wheels off it has a vertical acceleration of zero.
Help!
1 https://measuringly.com/how-much-does-boeing-747-weigh/ 2 https://aviation.stackexchange.com/questions/47422/what-is-t...
1) when an airliner lands, the undercarriage legs, which are telescopic sprung and damped struts, spread the vertical deceleration over a finite period (I cannot say how long it lasts, but I would say of the order of a second or so.)
2) At the point of touchdown, the wings are generating lift about equal to the aircraft’s weight. This decreases quite rapidly, largely on account of the decease in angle of attack as the nosewheel comes down and from the deployment of spoilers, but it would be mistaken to think that the runway is immediately supporting the full weight of the airliner after touchdown.
3) On takeoff, until the nosewheel is lifted to initiate rotation, a significant fraction of an airliner’s weight is being supported by the runway. During rotation, as the angle of attack increases, the lift increases [1] until it exceeds the weight, at which point the airliner lifts off.
4) If we ignore the fact that the undercarriage is sprung, then the airliner has no vertical velocity until it lifts off. Right at that point, however, when the lift exceeds the weight, it gains a vertical acceleration.
I hope this helps!
[1] Plus a vertical component of the engine thrust, but no airliner rotates to anything like 45 degrees - in fact, if it has not left the ground at a rotation angle equal to the angle of maximum lift coefficient (~10 - 15 degrees), it is not going to do so without going faster.
On take off f = 330 x 10 = 3300 (units etc)
On landing f = 160 x 10.7 = 1712
So, if you are gentle enough on landing and the aircraft is nearly half the weight it was on take off then the downward force on landing is very much less than that on take off.
That 160 tonnes empty also implies I've thrown the passengers, crew and luggage out too, which is a bit rough. Let's try total fuel at "about 180 to 213 tonnes" and allow that we need a factor of safety, so let's say 40 tonnes of fuel left over on landing.
On landing f = 200 x 10.7 = 2140
So, I'm still going to need some convincing about landing aircraft causing more damage than those taking off.
I was only waffling about rotation angles whilst trying to get to grips with what is going on. I now don't think the engines have anything to do with this analysis. Mind you I am just about old enough to remember watching Lightnings (https://en.wikipedia.org/wiki/English_Electric_Lightning) taking off. Imagine a large silver firework ...
I'm now curious about the engineering of the displaced threshold. This is a portion of the runway that aircraft can taxi onto and use for takeoff but not for landing. I thought (assumed) that the landing was harder on the runway surface than takeoffs, hence the displaced threshold wasn't designed for that force.
The displaced threshold could also be used to ensure obstacle and terrain clearance on landing - simply disallow that portion from being used in order to create an offset from the obstacle. But I don't know whether this is a very common reason for displaced threshold usage.
-- Video also mentions https://skybrary.aero/ which I'd not heard of previously. Looks neat. I'll have to check it out.
I'd be surprised that a heavier plane on takeoff exerts more force on the runway than a lighter plane landing.
And as the departing plane goes faster, doesn't the lift take stress off the runway?
Funily I was learning to fly at a grass strip and we were told to vary our positioning left and right on the runway for exactly this reason. In practice it meant that as we were taxiing to the runway my instructor would tell me “Today we are taking off left/right of center to avoid damaging the grass too much.”
Only for a short period between rotation and liftoff. Most of the takeoff roll is spent building up horizontal speed; the pilot doesn't command the aircraft to pitch up before it's ready to lift off.