Demystifying Garbage Collectors
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As an experiment, I tried writing a garbage collector which used high-order bits of a word to identify pointers. The result is about a page of code in Forth:
http://hastebin.com/raw/gabunowelo.fs
This example works exclusively with fixed-size "cons pair" allocations, but generalizing to arbitrary-sized allocations only increases the complexity of the system slightly. Obviously this bitflag technique is not "safe" in general, as arbitrary values on the stacks could produce false positives, but it's easy to imagine a 33-bit or 65-bit architecture that provided the necessary hardware support without such caveats.
http://stackoverflow.com/questions/106597/why-are-fixnums-in...
http://www.gnu.org/software/emacs/manual/html_node/elisp/Int...
SBCL has a more elaborate tag bit system:
See page 11 of: http://board.flatassembler.net/download.php?id=5698
Some x64 targeted languages already use tagged pointers without specific hardware support; e.g. I recall reading about JVM using several bits of object pointers in 64-bit to encode a class index, so that polymorphic inline caches can be checked without an indirection.
It can go even further than that; most systems only use 48 bits for addresses -- this leaves more than enough space to "NaN-box" objects by putting the address inside the extraneous bits of a 64 bit floating NaN.
How does the having the bottom 4 bits free in a pointer help if you can't use them to tell the difference between a pointer and an integer 1 or 2? He is asking for a reserved set of bits on every data type so that he can store minimal type information like pointer, not pointer.
Judging by benchmarks, it's a good thing they did. Byte-addressed but word-aligned pointers plus pipelining and superscalar processors (branch prediction probably helps too) give you almost the same performance as explicit instructions for tag support. The amount of flexibility and the simplification in the instruction set you get from it is well worth it IMO. SPARC had such instructions, and on benchmarks (see http://www.cs.ucsb.edu/~urs/oocsb/papers/oo-hardware.html and http://www.cs.cmu.edu/~ram/pub/arch.ps) the difference in speed between using them and not was less than 5%.
On a 64-bit machine, you have 30 different tags available (5 tag bits, since the smallest thing you'd want to point at is going to be two 64-bit words big, and two of the 5-bit patterns reserved for positive and negative fixnums, for 60-bit immediate integers).
The problem is a lot of algorithms (especially crypto) are designed around 32 or 64 bit words, which typically means you have to make contortions and declarations to have your compiler operate on immediate representations. Typically, the compiler will set aside some registers on the CPU for dealing with these immediate values, so the garbage collector doesn't get confused. On x86 this might mean you don't have enough registers to run the algorithm efficiently, even if the compiler knows exactly what needs to be unboxed.
Another problem is floating point values. On 64-bit systems there's a technique called NaN-boxing that can do something about this (http://wingolog.org/archives/2011/05/18/value-representation...), but I don't yet understand how it works.
I do agree on one thing - slapping an extra byte onto word size would be awesome, as long as that extra byte is general purpose. Other things besides tagging that you could do with it would be error-correcting codes (the Symbolics Ivory actually had ECC for every word), and all kinds of metadata. Maybe it would even make sense to keep this extra byte out of the memory bus and just have it on registers; that's where most of the trouble with tagged values on modern machines seems to come from. This would make sense for load/store instruction sets.
NaN-tagging works by using the unused variations of NaN for pointers. The trick is that most processors only generate a single binary pattern for NaN, so all other binary patterns are never used to represent floating point numbers, and can thus be used to represent pointers. This works since the current x64 implementations only use 48 bits for the pointers, so all pointers can "fit" into the remaining 52 bits of NaN.
On reading this I immediately read the standard, hoping to discover that the word "fraction" wasn't used, only to find that "fraction" is defined as the part of the significand (mantissa) lying to the right of the implied binary point. In essence then (because the bit to the "left" of the binary point is only ever implied, never explicit), "fraction" stands as a synonym for significand.
Unfortunate terminology. And why? Here's why:
A fraction: 1/3
A significand, base ten: 0.3333333333333333
IEEE 754 can provide the second, but it cannot provide the first.
IEEE 754:
http://kfe.fjfi.cvut.cz/~klimo/nm/ieee754.pdf
Significand:
http://en.wikipedia.org/wiki/Significand
A quote: "The significand (also coefficient or mantissa) is part of a floating-point number, consisting of its significant digits."
p.s. this is not a correction, it's a lament.
Remember, this is binary, so the only possible digits are 0 and 1. For example, 1/3 in binary is 0.01010101010101...;
Encoding that in "floating point", we first get:
1.0101010101 * 2^-2;
We can see that in this format, the first digit of the number is always 1; thus, the first digit of the significand, for any number, is ALWAYS 1 (in binary)! IEEE754 makes the optimization to not store this leading 1 as part of the fraction, so the the approximation to 1/3 is actually encoded as: 0 01111111101 0101010101010101010101010101010101010101010101010101
^ ^ ^
| +-----+ |
sign bit | fraction = 1.33333... = 1.01010101010101...0101010101010101b
| |--- this part is included ---|
|
exponent = 01111111101b - 1023 = 1021 - 1023 = -2I noticed that Jones has a new book (The Garbage Collection Handbook) out now, which presumably is even better: http://tinyurl.com/8nl6con
Rust is using this model today.
How lightweight are Racket places? I'm not very familiar with the language, so I don't know if they're really comparable to Erlang processes.
struct {
double a; // 64 bit
short b // 16 bit
int c, d; // 32+32 bit
FooPtr e; // 64 bit
int f; // 32 bit
BarPtr g; // 64 bit
}
Does it assume that all fields are aligned to 64 bit boundaries? Does it potentially consider a double to be a pointer? And how does it know where to stop looking for references without knowing the size of the object?
(Not strictly true - some runtimes have dynamically growing stacks, but the GC knows the size regardless.)
Most garbage collectors assume pointers to be aligned on a word boundary; that is on a 4-byte boundary on 32-bit machines and an 8-byte boundary on 64-bit machines. This is a reasonable assumption because accessing pointers that are not word-aligned is extremely slow on most architectures. It does not care how fields that don't contain pointers are aligned because their contents are irrelevant (so this translates to the compiler being able to pack some fields together without worrying about breaking the GC).
So, a conservative GC will simply scan over every word in an object and interpret it as a potential pointer, regardless of what it actually is. So yes - even a double will be considered a pointer.
As for your other questions, remember that a conservative GC manages objects allocated through it, not just random objects in the system. It can use allocator metadata to keep track of where objects start and how long they are.* It aligns objects to some multiple of the word size, and can ignore any bit pattern that doesn't point to some multiple of 4 or 8 bytes. It also knows the extents of its own heap. As its scanning pointers, it does some checks to see if a particular bit-pattern points outside of the heap or does not point to the beginning of an object. If a possible pointer passes all of these tests, it definitely points to an object. It might not actually be a real pointer, but the target is actually an object managed by the GC.
On a 64-bit machine, it's actually fairly rare for a random "int" or "double" to be mistaken for a pointer. Most "ints" are small integers, and on a 64-bit machine the heap is almost always allocated above 4GB. Similarly, the odds of a 64-bit double bit pattern pointing inside the heap out of all those exabytes of heap is unlikely.
*) This is similar to how a malloc implementation might use allocator metadata to know how big a chunk is for a free() call.