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The standard will be used, as it was the previous time the IETF allowed the NSA to standardize a known weak algorithm.

Sorry that someone calling out a math error makes the NIST team feel stupid. Instead of dogpiling the person for not stroking their ego, maybe they should correct the error. Last I checked, a quantum computer wasn't needed to handle exponents, a whiteboard will do.

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ML-KEM and ML-DSA are not "known weak". The justification for hybrid crypto is that they might have classical cryptanalytical results we aren't aware of, although there's a hardness reduction for lattice problems showing they're NP-hard, while we only suspect RSA+DLog are somewhere in NP. That's reasonable as a maximal-safety measure, but comes with additional cost.

Obviously the standard will be used. As I said in a sibling comment, the US Government fully intends to do this whether the IETF makes a standard or not.

Worth noting this concern over as-yet-undiscovered cryptanalytic techniques also applies to Bernstein's preferred SNTRUP.

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