(but your point about the title is valid)
Can you pass the T-shaped tetromino through itself?
From their About page: Quanta Magazine is an editorially independent online publication launched by the Simons Foundation in 2012 to enhance public understanding of science.
- "Researchers Discover the Optimal Way to Optimize"
- "Origami Patterns Solve a Major Physics Riddle"
- "A simple way to measure knots has come unraveled"
- "The Hidden Math of Ocean Waves Crashes Into View"
I don't necessarily mind it, even if I don't find the articles very informative. But it's certainly fair game to nitpick this borderline-clickbait style.The "pass through itself" criteria is the same as "has one shadow that fits entirely inside another shadow". If you allow "one shadow equals another shadow" then it's trivially true for every shape because a shadow equals itself.
Note that this "shadow" language assumes a point light source at infinity, i.e. all the rays are parallel.
A sphere is a surface of constant width, which the polyhedron approximation is not.
> The projected shadow has the same size as its diameter
Thus this is exactly why the sphere doesn't have the Rupert property.