But I'm going to go out on a limb here and guess you don't do that. You actually do allow the C++ compiler to make assumptions that are not explicitly in your code, like reorder instructions, hoist invariants, eliminate redundant loads and stores, vectorize loops, inline functions, etc...
All of these things I listed are based on the compiler not doing strictly what you specified but rather reinterpreting the source code in service of speed... but when it comes to the compiler reinterpreting the source code in service of safety.... oh no... that's not allowed, those are training wheels that real programmers don't want...
Here's the deal... if you want uninitialized variables, then explicitly have a way to declare a variable to be uninitialized, like:
int x = void;
This way for the very very rare cases where it makes a performance difference, you can explicitly specify that you want this behavior... and for the overwhelming majority of cases where it makes no performance impact, we get the safe and well specified behavior.And if you used it with a default value of 0, you're going to end up operating on the 0th item in the array. That's probably a bug and it may even be a crasher if the array has length 0 and you end up corrupting something important, but the odds of it being disastrous are much lower.
If they added an explicit uninitialized value representation to the language, I bet it would look something like this:
int x {std::uninitialized<int>::value};std::nullopt doesn't seem so different to what I was talking about; I guess it's just less verbose. When I wrote that, I was thinking of things like "std::is_same<T1, T2>::value" being there.
int x [[indeterminate]];
I'm not kidding here;The whole idea of optimizations is producing code that’s equivalent to the naiive version you wrote. There is no inconsistency here.
https://godbolt.org/z/Y4Yjb7z9c
clang notices that in the second loop I'm multiplying by 0, and thus the result is just 0, so it just returns that. Critically, this is not "exactly and only what the programmer specifies", since I very much told it to do all those additions and multiplications and it decided to optimize them away.
https://godbolt.org/z/jzWWTW85j
Compile that without optimizations and you get one set of output, compile it with optimizations and you get another. There are actually an entire suite of exceptions to the "as-if" rule.The second point is that the whole reason for having an "as if" rule in the first place is to give permission for the compiler to discard the literal interpretation of the source code and instead only consider semantics that are defined to be observable, which the language standard defines not you the developer.
There would be no need for an "as if" rule if the compiler strictly did exactly what it was told. Its very existence should be a clue that the compiler is allowed to reinterpret the source code in ways that do not reflect its literal interpretation.
What does this mean since I am not writing assembly and there is no specified correspondence between assembly and C++.
I'm not sure why you're bringing up assembly but it suggests that you might not correctly understand the example I provided for you, which I reiterate has absolutely nothing to do with assembly.
I agree you have a valid point though. I'd be interested to know the committee's reasoning.
this is what the D programming language does. Every var declaration has a well know value, unless it is initialized with void. This is nice, optimizing compilers are able to drop useless assignments anyway.
Would it really be that unreasonable to have initialisation be opt-out instead of opt-in? You'd still have just as much control, but it would be harder to shoot yourself in the foot by mistake. Instead it would be slightly more easy to get programs that can be optimised.
I'm more annoyed that C++ has some way to default-zero-init but it's so confusing that you can accidentally do it wrong. There should be only one very clear way to do this, like you have to put "= 0" if you want an int member to init to 0. If you're still concerned about safety, enable warnings for uninitialized members.
The almost is unfortunate.
Things can change & grow, that's why we make new standards in the first place.
In a sane language that would be distinguishable by having the direction explicit (i.e. things like in/out/ref in C#), and then compiler could complain for in/ref but not for out. But this is C++, so...
A programmer wants the compiler to accept code that looks like a stupid mistake when he knows it's not.
But he also wants to have the compiler make sure he isn't making stupid mistakes by accident.
How can it do both? They're at odds.
By doing what’s right.
https://en.wikipedia.org/wiki/Principle_of_least_astonishmen...
And that's not just said out of unfamiliarity. I'm a professional C++ developer, and I often find I'm more familiar with C++'s more arcane semantics than many of my professional C++ developer co-workers.
Many of these can't be blamed on C holdover. For example Vector.at(i) versus Vector[i] – most people default to the latter and don't think twice about the safety implications. The irony is that most of the time when people use std::vector, performance is irrelevant and they'd be much better off with a safe default.
Alas, we made our bed and now we have to lie in it.
So, do you?
int i;
does not initialize the value. #include <string>
struct T1 { int mem; };
struct T2
{
int mem;
T2() {} // “mem” is not in the initializer list
};
int n; // static non-class, a two-phase initialization is done:
// 1) zero-initialization initializes n to zero
// 2) default-initialization does nothing, leaving n being zero
int main()
{
[[maybe_unused]]
int n; // non-class, the value is indeterminate
std::string s; // class, calls default constructor, the value is ""
std::string a[2]; // array, default-initializes the elements, the value is {"", ""}
// int& r; // Error: a reference
// const int n; // Error: a const non-class
// const T1 t1; // Error: const class with implicit default constructor
[[maybe_unused]]
T1 t1; // class, calls implicit default constructor
const T2 t2; // const class, calls the user-provided default constructor
// t2.mem is default-initialized
}
That `int n;` on the 11th line is initialized to 0 per standard. `int n;` on line 18, inside a function, is not. And `struct T1 { int mem; };` on line 3 will have `mem` initialized to 0 if `T1` is instantiated like `T1 t1{};`, but not if it's instantiated like `T1 t1;`. There's no way to tell from looking at `struct T1{...}` how the members will be initialized without knowing how they'll be called.C++ is fun!
[0]https://en.cppreference.com/w/cpp/language/default_initializ...
> "There's a great language somewhere deep inside of C++"
or something to that effect.
(the original pre-ISO C++ is basically C with Simula bolted onto it.)
> The results show that, in the cases we evaluated, the performance gains from exploiting UB are minimal. Furthermore, in the cases where performance regresses, it can often be recovered by either small to moderate changes to the compiler or by using link-time optimizations.
Most programmers aren't that good and you're mostly running other people's code. Bad defaults that lead to exploitable security bugs is...bad defaults. If you want something to be uninitialized because you know it then you should be forced to scream it at the compiler.
idk, seems like years of academic effort and research wasted if we do the way C++ do it
Good luck with that.