Do the payout between 0 and 1 as the percentage of the amount.
With a range of 1 to 1 to pay off is obviously one
With a range of 1 to 2 the payout is .5
At three values it becomes more interesting. There are two strategies for the candidate either a binary search for the endpoints.
At four values you still have one level of binary search possible but after that it devolves down to the two value problem.
At five values. If the interviewer thinks the candidate would choose binary search and it becomes too too value problems on each side after removing the middle element.
There's definite problems with this but I wonder if he's already possible pay off matrix