This is generics.

Calling x.some_func() in rust means there is either a type specific function or an impl trait. If more than one option is there rust requires more explicitly calling the types function with x as a parameter.

E.g.

Something::some_func(x)

I’ve never read rust code where I’m entirely guessing which overloaded function is being called. C++ has an entire set of overload resolution rules around this! https://en.cppreference.com/w/cpp/language/overload_resoluti...