I'm confused because isn't the bitwise version the inverted logic? If the LSB is 1 then it is an odd value, which should be zero, yet that is shifted to become 32. The original modulus is for an even value becoming 32. Shouldn't the original code or compiler invert it first? I'd expect
let shift = ((~(i >> 5) & 1) << 5);
EDIT:
The compiler uses "vpandn" with the conditional version and "vpand" with the bitwise version. The difference is it includes a bitwise logical NOT operation on the first source operand. It looks like the compiler and I are correct, the author's bitwise version is inverted, and the incorrect code was merged in the author's commit. Also, I think this could be reduced to just (~i & 32).