Are you never not inside a called function?
This just sounds like pervasive mutability with more steps.
Are you never not inside a called function?
This just sounds like pervasive mutability with more steps.
You typically wouldn't just write a Genserver to hold state just to make it mutable (though I've seen them used that way), unless it's shared state across multiple processes. They're not used as pervasively as say classes in OOP. Genservers usually have a purpose, like tracking users in a waiting room, chat messages, etc. Each message handler is also serial in that you handle one mailbox message at a time (which can spawn a new process, but then that new process state is also immutable), so the internal state of a Genserver is largely predictable and trackable. So the only way to mutate state is to send a message, and the only way to get the new state is to ask for it.
There's a lot of benefits of that model, like knowing that two pieces of code will never hit a race condition to edit the same area of memory at the same time because memory is never shared. Along with the preemptive scheduler, micro-threads, and process supervisors, it makes for a really nice scalable (if well-designed) asynchronous solution.
I'm not sure I 100% agree that watching mutating state requires a function to observe it. After all, a genserver can send a message to other processes to let them know that the state's changed along with the new state. Like in a pub-sub system. But maybe he's presenting an over-simplification trying to explain the means of mutability in Elixir.
If so, this sounds a lot like IORef in Haskell.
If you call `Process.put(:something, 10)`, any references you have to whatever was already in the process dictionary will not have changed, and the only way to "observe" that there was some mutating state is that now subsequent calls to `Process.get(:something)` return a different value than it would have before.
So with immutable variables, there is a strict contract for observing mutation.