Apply for Sunshine
reflectorbital.com
reflectorbital.com
More to the point, why does that shop advertise to anybody other than gov agencies with deep pockets and a strong interest in remote sensing?
So in order to receive this beam efficiently, you would need a solar array 5 km in diameter with 100% ground coverage. Efficiency decreases if the array is smaller or less dense. Maybe you could use a curved mirror to focus the beam to a smaller diameter, but that seems more difficult than spinning a flat mylar sheet.
Assuming you had such an array, every 1 m^2 of mirror should provide roughly as much power as 1 m^2 of panels on the ground.
Verification: https://www.wolframalpha.com/input?i=5km+%2F+500km+*+1+AU = "1.1 x mean diameter of the sun"