So you are going to get a lot of funny explanations of why you can still say “ℤ ⊂ ℚ” and what that means. And what is “the same as” anyway?
So you are going to get a lot of funny explanations of why you can still say “ℤ ⊂ ℚ” and what that means. And what is “the same as” anyway?
N is the set of zero and all its successors.
Z is N extended with all additive inverses, which means it includes all of N.
Q is Z with all multiplicative inverses, so it includes all Z.
R is the set of Q plus all supremums and infinums of all bounded sets of Q.
R is only not Q when you define R with dedekind cuts, which is a nice formal construction, but doesn't change what R is, up to isomorphism.
Which is exactly the sort of more sophisticated notion of equivalence you end up needing in these cases.
I'm pointing out that the nature of R is independent of its definition, and that any mathematical formal system you invent to construct R (up to isomorphism) is just a description. R exists independently on its own.
The constructions of R are useful, because you can show things about them that could be applicable to R.
However, the article gives a rhetorical question of whether you should be able to say 0 is in 3. No you should not, because while there are many constructions of the natural numbers, the universal property they all share (that there is a zero and a successor) does not permit any notion of inclusion. The construction of the naturals as sets would permit such notions, but these are not relevant to any discussion of the natural numbers.
Put in homotopy type theory terms, the natural numbers are the equivalence class of all representations of the natural numbers, and all propositions over the natural numbers are the equivalence classes of all propositions over all representations of the natural numbers.
Since one cannot draw an equivalence between '0 \in 3' and any proposition from another construction of the natural numbers (I believe), then the term '0 \in 3' is not a proposition over the natural numbers.
Put another way, I posit that there are constructions isomorphic to the natural numbers whose propositions cannot be mapped onto the space of all propositions over the construction of the natural numbers as sets. Whereas, all constructions of the natural numbers will permit a proof of the associativity of addition, or the infinity of primes. So these proofs are what should be accepted as 'proofs' over the natural numbers, but '0 \in 3' would not, because it's missing in many systems. '0 \in 3' could be used in the set representation to be the definition of less than, but it is not a statement that applies to all representations.
Is that clearer?
Isn't that a bit metaphysical and open to interpretation? I would say R only meaningfully exists as defined. A mathematical "truth" is either an axiom or it has a proof?
(Not that I think that makes a difference for the original argument about 1)
There is an infinite chain of supersets of the rational numbers, real numbers, etc.
Think of it like this… we can define 0, and then define 1 as the successor. Repeating this, we can have a definition for every finite number. But we cannot do this the other way around. We cannot start with ∞, define the predecessor to ∞, and then somehow get back to 0.
In other words, if you want to work backwards and say that smaller sets (like the natural numbers) are a subset of the bigger sets (like complex numbers), then you have to pick a “biggest set” containing all numbers, which is unsatisfactory. Somebody always wants a bigger set.
I have thought about this too, and I'd initially agree with you. but I thought at some point how mathematical history is not extremely dissimilar from this. put in very rough terms:
at first humans discovered/invented numbers (i.e. the counting numbers); these started at number one — the first number. later on, at some point we had to go back and realize that there was a zero before number one which "silently" redefined the first number as zero and this created the natural numbers a the modern set-based N
edit: adding this alternative rendering of my intended comment triggered by a condescending reply: "mathematics silently redefines stuff all the time. deal with it"
[I believe this YouTube video goes into more detail in its discussion of why 1 was not considered Prime in the ancient world: https://youtu.be/R33RoMO6xeA]
No you only do it for all the sets (of numbers) that you are currently working with.
Exactly what we did in the Analysis I course I attended during my bachelor: defined the reals axiomatically, and the N as smallest inductive(?) subset containing 0.
Satisfactory or not, it worked well for the purpose. And I actually liked this definition, if anything because it was original. Mathematical definitions don't need to have some absolute philosophical value, as long as you prove that yours is equivalent to everyone else's it's fine.
That’s exactly the point I was making in the first place.
“Unsatisfactory” just means “unsatisfactory” in the sense that some mathematicians out there won’t be able to use your definitions and still get the subset property. This means that you are, in all realities, forced to deal with the separate notions of “equivalence” and “equality”. Which is what the article is talking about—all I’m really saying here is that you can’t sidestep equivalence by being clever.
In the end you still need to maintain a correspondence between the embedding and the original set as in the typical way where you do that and consider the subset notation as a shorthand that requires you to "lift" or "wrap" through the correspondence wherever necessary.
Collapsing a countably infinite set to 0 doesn't seem useful or reversable.
I'm not sure what you're trying to disagree with here.
Not heaps sure what this really means with respect to whether 1 the integer is really completely related (as in, equal, or the-exact same-thing) to 1.0 the real though. Kinda seems like it might still need a bit more information to fully identify a real, even when it happens to be infinitely-close to an integer?
Q = Z u Q’, where Q’ is the set of all rational numbers that aren’t integers.
Redefining the smaller set can’t work because there may be more than one larger set, e.g. split complex numbers vs regular complex numbers. But you can define a larger set to strictly extend a smaller set.
Is there some integer that is not also a rational number?
In the natural numbers,
0 = {}
However, {} is not an element of the integers.This is not something I expect to be easy to understand. This is the standard set theoretic definition of integers that mainstream mathematicians use. This is not some esoteric, fringe theory.
A quick look at Wikipedia indicates that there exist other constructions.
You could pick a construction where the natural numbers are a subset of the integers. This is trivial, but this is a poor strategy overall, because you can always find a bigger set of numbers to work with. You can’t take the “biggest” set of numbers and then define all other sets of numbers as subsets of that. It would be kind of like trying to count down from infinity.
It looks like the approach of defining ℤ in terms of ℕ is much more tedious to deal with overall, so can see the advantages.
It's a bit like saying every int32 is also a double. Yes, every value of int32 fits into a double, but the bit pattern is different.
The canonical construction for rational numbers is pairs (a, b) which we interpret as a/b. An integer k "is the same as" (k, 1).
So it might be more correct to say every integer has the same value as some rational number. Of course this distinction is pointless most of the time, so we don't worry about it.
This is not unique to integers and rationals. It also applies to naturals and integers, rationals and reals, etc.
However I assumed that this is only a problem in programming languages. I am a bit surprised that mathematics also seems to be affected. I am going to study it a bit.
In the pre-rigorous stage, you don't know it's an issue. In the rigorous stage, you know it's an issue. In the post-rigorous stage, you know it's not an issue (i.e. you know you know how to write down all the details if you needed to, and you know it will all work how you might hope it would, and so you don't need to).
An isomorphism is a way to relate two different sets such that each element is paired with exactly one in the other set such that it does not matter if you do operations before or after.
In my calculator the set of reals is isomorph to the set of complex numbers with imaginary part zero:
ℝ ⬄ { c | c ∈ ℂ and im(c) = 0 }
So I can coerce to complex numbers without impunity because of that isomporphism! And I know it is an isomorphism because if adding two reals then coercing to complex is the same as coercing first then adding.TIL: In a way mathematics has types like programming languages.
I hope I am not too far off here. I didn't look up anything, this all went into my head this morning.
The closest thing I'm aware of to "pretty much equal" is "unique up to unique isomorphism", so they may not be equal, but they're isomorphic, and there's no flexibility to make any choices of which isomorphism to use. But "isomorphism" also implies you have a particular context/structure in mind that you want to preserve, e.g. a set isomorphism (a bijection) may not be a linear isomorphism (~an invertible matrix). In practice, you may be working in multiple contexts at once, so you invent Functors which map one type of morphism to another, and now you care about Categories.
In the same way the real line is "included" in the plane (\R \times \{0\}) or the sphere is not only a subset of the whole space but a submanifold.
Math uses lots of polymorphism and overloaded notation, but that is also part of the beauty, where "A=A" can actually be a deep result about concepts being compatible.
??
Are you claiming that ℤ ⊄ ℚ
This thread is wild.
So in most case, mathematicians and non mathematicians just write Z ⊂ Q and live happily ever after. But if you get supertechnical you should use scare quotes Z "⊂" Q or to look more proffesional Z ↪ Q (because tha inclusion is an injective funcion, and sometimes it's useful to think aboout it as a function.).
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To add some confussion: Imagine that you buy in the supermarket a copy of Z that is green and another copy of Z that is red.
1(red) + 2 (red) = 3(red)
1(green) + 2(green) = 3(green)
(If I get super technical, I have to define a +(red) operation and a +(green) operation. And probably also a =(red) and =(green) as the article discuss.)
Are they the same Z or just canonicaly isomorph or it doen't matter?
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To add even more confussion: You have a copy of abstract Z and a copy inside the rational written as n/1:
1 + 2 = 3
1/1 + 2/1 = 3/1
Are they the same Z or just canonicaly isomorph or it doen't matter?
Actually, the statement ℤ ⊂ ℚ reads "The set of integers is a proper subset of rationals."
I think the real funky business happens right between ℚ ⊂ ℝ
but maybe all I'm really trying to say is "hey, look at me, I understand how all of ℕ ⊂ ℤ ⊂ ℚ"
I'm very very sure that it's possible to give a fully ZF set-theoretic construction of the rationals using sets. in fact IMO the annoying thing is that there are in fact two trivially equivalent constructions that I can think of the top of my head, and I find that even worse than there being none at all
Traditionally, you define ℚ as equivalence classes of pairs of integers. The integer 0 is an integer, it’s not an “equivalence class of pairs of integers” and therefore it’s not a rational, in the set-theoretic sense.
Real numbers have lots more constructions.
https://en.m.wikipedia.org/wiki/Construction_of_the_real_num...
I gotta figure out dedekind cuts or at least learn tarski's fixed point theorem which I'm sure that would allow me to much better understand tarski's construction
all in the slow lifelong process of understanding and learning to draw post's lattice
finally, to answer your question, I disagree with saying that there's funky business between ℤ ⊂ ℚ because of my alleged claim that there is at least one construction which avoids the problem you describe, but as I was trying to say, these would have a non-unique way to construct number zero which nobody likes
If you do it that way then there is only one version of “1”