The shutter speed was 1/250th of a second, so the earth rotated about 4 miles or 6 kms while the shutter was open. Not enough to blur the photo obviously, but crazy to think about.
$ units "2 * pi * moondist / (27.3 day) * (second / 250)"
Definition: 4.0958765 m
Circumference is 24,901 - so about 1000 mph at equator.
1000 mph / 3600 s / h = 0.27 mps
0.27 * (1/250) = 0.001 miles?
Doing this math on my phone but am I missing something here?
Earth's orbital speed: 66,200 mph
66,200 mph / 3600 s/h = 18.38 mps
18.38 * (1/250) = 0.07 miles
$ units '2 * pi * earthradius / day * (second / 250)'
Definition: 1.8532517 m
360/86,400=0.0041667deg/sec
0.0041667 * 0.004sec = 000016667degR
circumference:
2pi * 6371km = 40,030km
land covered by rotation:
40,030 / 360 = 111.194km/deg
0.000016667deg × 111.194 km/degree = 0.001854 km
km to m:
0.001854km × 1,000 meters/km = 1.854 meters
more like 0.001 miles. ... oh, woops. I see your answer is in kms.
it was something like 0.46km/s.
Or if the orbital velocity was 17,000 mph and neglecting the height of the orbit, 17000 / 3600 / 250 = 0.018 miles.
So either way, about 100 feet.