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If my math is right, the angular resolution of the EHT is such that you could image an object just 99m across on the surface of the moon. Or a 2in object could be resolved from a low earth orbit satellite. Not bad.

They are imaging an object 0.6ly across at a distance of 250M ly or so. Just insane.

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I don't know if 99m would be possible due to the focal point tied to the diameter of the lense (in this case roughly earth sized with the EHT) Please correct me if that's incorrect though

Oh, I'm just making an analogy; of course you would never use the EHT to image something on the moon.

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