because 1 \and 0 = 0 same as 1 * 0 = 0
and 1 \or 0 = 1 same as 1 + 0 = 1
It is equally true that 1*0=0 is the same as false|true=true, and 0+1=1 is the same as true&false=false.
But it is also not true that 1+1=1, so it is probably wrong to equate 'or' with '+'. The operation has the wrong properties.
As someone who sometimes dabbles in electronics, 0 = true makes a lot of intuitive sense to me. You have your pin with an open collector, your pull-up resistor, and “true” (as in, it is true that the transistor is conducting) pulls the voltage to ground, which is 0.
As someone who uses a Unix shell, 0 = true makes a lot of intuitive sense to me.
$ true; echo $?
0
$ false; echo $?
1> You can interpret "A or B" as a set union and "A and B" as a set intersection.
{True, False, Or, And} and {False, True, And, Or} are two different naming conventions for the exact same structure: the unique boolean algebra on two elements.