Math That Goes on Forever but Never Repeats
quantamagazine.org
quantamagazine.org
● ● ○ ● ● ○ ● ○ ● ● ○ ● ● ○ ○ ● ● ○ ● ● ○ ● ○ ● ● ○ ● ● ○ ○ ● ● ○ ● ● ○ ● ○ ● ● ○ ● ○ ○ ● ● ○ ● ● ○⋯
I put a brief description up on it here:
Edit: I wonder if you can use property based testing to prove this fact...
○ ● ● ○ ● ○ ○ ● ● ○ ○ ● ○ ● ● ○ ● ○ ○ ● ○ ● ● ○ ○ ● ● ○ ● ○ ○ ● ⋯
I don't think this contains any 'anti pattern game' losing sequences, but I may be missing something.
The article title is correct, but the article page's HTML title is wrong / SEO
Could you also be more precise about what you mean by true randomness?
Edit: let’s not forget the rich theory involved in examining if sets/sequences contain arithmetic (or geometric) progressions! The well known Green-Tao theorem about primes containing arbitrarily long arithmetic progressions is one such result. In fact, the real Green-Tao theorem says that any set which has nonzero upper density with respect to the set of primes contains arbitrarily long arithmetic progressions.
All the repeating sequences have finite Kolmogorov complexity. So, if you want, you can say that the sequences with infinite Kolmogorov complexity have even lower repetitiousness than the ones we can produce algorithmically. And this will go on and on through the countable ordinals.
Isn't this just true?
The set of algorithms is countable, and the set of sequences of real numbers is uncountable.
You're kind of "begging the question" here, where you're assuming that non-computable numbers exist and then using that to show that some numbers are non-computable. You can definitely show that these things exist, but that relies on "believing" the set of axioms that you used to prove it.
My understanding is that we can reason about these sorts of non-constructible sequences but we can't really know if they "really exist" because it's not clear what that even means if their existence has no implications for physical reality (which is possible but not known). So now we're into the territory of whether there is such a thing as abstract truth independent of reality.
I wrote a blog post in the past about my reading on this topic, and I can't claim that's it's accurate but at least I tried to talk about this subject: https://blog.kevmod.com/2022/04/09/do-the-real-numbers-exist...
That is assuming finite algorithms. I’m curious if infinite algorithms exist and/or considered in maths.
The internet says that an algorithm is finite by definition, but it’s hard to search for “infinite algorithm” because everyone talks about termination instead.
After playing with the tiles a little bit it seems to me that placing 4 (maybe even 3) hats on top of each other is one such configuration. You can place 1-2 more tiles on each side, but you quickly endup with state where the dead end is obvious.
DOWN UP UP DOWN
This is the UP-pattern. The DOWN-pattern is UP DOWN DOWN UP.
Then I'd do it again, but replacing every DOWN with the DOWN-pattern and every UP with the UP-pattern.
Then I'd try to do it again for that pattern. I don't remember how deep I could get. It wasn't very far! But I loved doing it.
Decades later I met someone who had done the exact same thing as a kid, though he called it LEFT RIGHT and moved his tongue around to do it, rather than tapping it out with his fingers.
Technically I ALSO did it left to right, I just didn't think of it that way. For UP-pattern I'd tap, or really roll/drum, left-to-right, index-middle-ring-pinky. And DOWN-pattern was tapped right to left.
As an adult I discovered it's called the Thue-Morse sequence.
It has a lot of fascinating properties that I think you'll be as delighted to learn about as I was.
while True:
i += 1
Also never repeats..ints(8-128) will either wrap around (repeating) or will overflow error in any language I've ever used
The age of the universe in Planck time requires 200 bits to represent as an integer.
The number of Planck cubes in the universe can be represented with 611 bits.
1 KB can represent an integer as large as 2^8000 = 10^2408. 10^2408 Planck times is 10^2347 x (age of universe). The last of the stars will burn out in 10^73 Planck times from now.