Now going from circuit theory to physics, we would see that inductance is not the property of an individual component called the "inductor", but it's the result of the magnetic field of the current around a closed loop of a circuit. Thus, every circuit must have a parasitic inductance. To a first approximation, this inductance is proportional to the loop area enclosed by the circuit. Thus, for high-speed digital / RF signal transmission, we often want to make the return conductor be as close to the signal conductor as possible [1]. This is why ground planes are often used in circuit boards, and why twisted pairs are often used in cables.
[0] The point of transition depends on many factors, including the physical size of the circuit. Sometimes it can be as low in the 100 kHz range.
[1] I ignored the issue of characteristic impedance
School physics teaches us that metals are perfect conductors of electric field, so the field in the large conductor should be the same across it, and not follow the L shape.
But it's only true for a stationary situation, basically DC. At higher frequencies the fact that the conductor (every part if it!) has some capacitance and inductance starts to play a major role in how a fast-changing signal propagates over it. Both the capacitance and the inductance of the part of the large conductor under the L-shaped conductor on the other side are affected by the L-shaped conductor.
These considerations could help see the result as "more intuitive".
I was also a bit surprised by this. But I do recall doing equations regarding capacitive and inductive reactance. In both cases there is a frequency-dependent effect which alters the shape of the waveform. It being frequency dependent, it disappears in the presence of DC (inductors becoming irrelevant and capacitors becoming nonconductive).
So I can kind of see it. But not enough to turn it into a return-path-is-suprising type example.
Basically, capacitance and inductance are important for oscillating signals. And that plane has a huge capacitance.