It requires a 2 mA to operate; that doesn't mean you're forced to actually draw 2 mA from the output.
From the datasheet
>all quiescent operating current is returned to the output terminal. This imposes the requirement for a minimum load current. If the load current is less than this minimum, the output voltage will rise.
I've used an LM317 drawing less than 2mA, so I assumed it was possible (in hindsight I must have used the solution, below).
The solution is very simple however, make a separate parallel circuit that will draw at least 2mA. This can be accomplished just by placing a resistor of appropriate value between the Vout and ground.
different types (small,large case) of LM317 havemaybe different parametrs