(mathematicians: is that right?)
(mathematicians: is that right?)
Here is a list of undecidable statements in ZFC: http://en.wikipedia.org/wiki/List_of_statements_undecidable_...
These models can look very strange. For example, if ZF is consistent, then by the Second Incompleteness Theorem so is ZF + "ZF is inconsistent". By the Completeness Theorem, a model for this theory must exist. In this model ZF is inconsistent, so there is a 'proof' of a contradiction from the axioms of ZF. However, since we have assumed the consistency of ZF, such a 'proof' must necessarily involve nonstandard integers.
Also not the OP's reply (paraphrased): "Thanks, but I wasn't interested in the understanding logic or math. I am thinking more along the lines of [metaphysical gobbledygook]. What can you say about that? "
If you do that, you could wonder what your new arithmetic looks like. This is actually very interesting question. Since "not G" says basically "it's not true that there's no proof of me", or, more specifically, "it's not true that there's no number that represents the proof of me", it's clear that "not G" asserts the existence of a certain "natural" number being the proof of G, which is not one of the natural numbers we know (since no "regular" natural number represents the proof of G). In our new universe there are "natural" numbers that you cannot reach by counting. Because of that, one can construct many different nonequivalent "implementations" (models) of PA + not G, which are necessarily different than the standard implementation of artihmetic we know (1, 2 = S(1), 3 = S(S(1)), ..., n = S(S(...S(1)...)), with + and *).
What is interesting about incompleteness theorem is that no matter if we add arbitrarily large number of axioms to PA, or even infinite number of axioms generated by computer program we write, the resulting system will still be incomplete, and each will have its own (many of them, actually) Goedel sentence.