Is the new discovery that there is actually a fifth layer, which is solid, and that what we previously thought of as the "core" is actually liquid and not the innermost layer?
Is the new discovery that there is actually a fifth layer, which is solid, and that what we previously thought of as the "core" is actually liquid and not the innermost layer?
This article states that the inner core has two different concentric zones that have very different crystalline properties. In particular, the inner sanctum is anisotropic with respect to seismic wave propagation, and the outer sheath of the inner core is much more isotropic. This suggest that they have different geologic histories--the innermost core's crystallographic anisotropy may have resulted from an event early in Earth's history that deformed the crystals, much as mountain building events deform the crystals in Earth's crust and upper mantle. Then, the younger outer sheath of the inner core cooled and crystallized around the older inner bit later on, after the deforming event transpired.
Are both of these zones “solid” states of matter? Or does our intuition about states of matter not really work for materials at these exotic temperatures and pressures?
Rather, the Earth's magnetic field is due to currents flowing in the liquid outer core. Convection in the core drives the conductive metal across these currents, increasing them by a dynamo effect. This process occurs on a rather small scale and is difficult to model, and is also somewhat chaotic, leading to very occasional collapses and flips of the Earth's magnetic field.
https://en.wikipedia.org/wiki/Geomagnetic_reversal
https://www.usgs.gov/media/videos/pubtalk-72004-secrets-ston...
https://upload.wikimedia.org/wikipedia/commons/thumb/7/74/Ma...
It would still be bad for us, but not something worth worrying about right now.
Or is that not a valid distinction in this case?
[0]http://hyperphysics.phy-astr.gsu.edu/hbase/Mechanics/sphshel...
I don't think that's what OP means. He's saying that the gravitational force that acts on a given test particle that's located inside Earth at a radius r=R from the center is determined only by the amount of mass "below it", i.e. the mass inside the ball of radius R, not the matter making up the spherical shell R < r < R_E, where R_E is Earth's radius. Put differently, that (hollow) spherical shell does not cause any gravitational force on test particles inside it.
This is absolutely correct and a consequence of Gauß's law, see https://en.wikipedia.org/wiki/Gauss%27s_law_for_gravity
Meanwhile, you are talking about a different thing entirely: The pressure. The matter above (as well as below and next to) our test particle will obviously also experience gravity and get pulled down. So our test particle will experience an isotropic force from all sides, which is generally quantified as pressure (force per area). This pressure is obviously not zero (but no one ever claimed that) and does depend on the radius of the outer spherical shell above it, in the same way as the pressure under water depends on how deep you are.
That is, the core doesn't feel gravitational pull towards the outside, because it's balanced on that other side, but the outside is being pulling in towards the core, which pushes on the core.
It might be easier to simplify the mental image by picturing just a slice of the whole thing.
Another way to think of this is to imagine a small sphere (like the size of a basketball) around the very center of the Earth. The matter in that sphere feels no net gravitational force, but it has to push back against the entire mass of the rest of the Earth, which is trying to fall into it.
However a shell of liquid is not self supporting, and at the size of a planet pretty much all material behaves like a liquid more or less. This means something needs to be pushing back for the layers of material to stay where they are. That is the pressure you feel, and you can easily show it will increase as you go down (with each layer supporting all the layers above it).
If anything the shell theorem makes this worse because it means the top layer can't pull back on any of the layers below it, it can only be pushed back through sheer pressure.