One day, if I really get into quantum mechanics, I will try to understand how they rebuilt maxwell equations from QED.
One day, if I really get into quantum mechanics, I will try to understand how they rebuilt maxwell equations from QED.
This derivation is in the context of classical field theory, but QED is only a short hop away through path integrals.
It’s quite remarkable how the complexity of Maxwell’s equations can be reduced to a single term in the Lagrangian - (F_uv)(F^uv), assuming no charges. That’s really it!
This can be explained through phase decoherence. As temperature rises, random phase shifts are introduced, which effectively removes the quantum effect. You can show mathematically how this works.
Consider the young experiment:
For a plane wave ψ ~ e^(ipx/ħ-iωt), the wave function at X is the sum of two components
<X|ψ> = <X|P> + <X|Q>
Where for some path-independent normalization function ψ(X,t), and using the small angle assumption (QX-PX = 2Xa/L), the components are:
1 ipXa/ħL
<X|P>= ψ(X,t)- e
2
1 -ipXa/ħL
<X|Q>= ψ(X,t) - e
2
And the probability of finding the particle at X is 2 2 2 pXa
|<X|ψ>| = |ψ(X,t)| cos -----
ħL
That is what you'd expect from the Young experiment. If we introduce a constant phase shift ϕ between P and Q, you get this average instead: 2 2 2 pXa
|<X|ψ>| = |ψ(X,t)| cos (--- + ϕ)
ħL
If this phase shift is instead random, the formula becomes 2 1 ^ pXa 2
|<X|ψ>| - (1 + | dϕ P(ϕ)cos(2 --- + 2ϕ)) |ψ(X,t)|
2 v ħL
Where P(ϕ) is a probability function for the phase shift. If the probability function is flat, the integral is zero since you're integrating the cosine across its domain. What you get is the classical result! 2 2
|<X|ψ>| = |ψ(X,t)|
You can even re-phrase random phase shifts into a diffusion equation, and find that given α as the diffusion coefficient 2 2 1 -αt 2 pXa
|<X|ψ>| = |ψ(X,t)| - (1 + e cos (--- + ϕ) )
2 ħL
i.e. the transition behavior from quantum to classical dependent on a direct measure of the decoherence!α small => quantum result, α = large, classical result.