Comment by olsgaarddk | Hacker News Reader

Comment by olsgaarddk | Hacker News Reader

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I thought I was pretty good at regex, but I could never have written this one and had to consult both `man grep` and regex101.com.

Explanations for the beginner and intermediate regex and grep user:

`-o`: Only return the match, instead of the entire line

`-P`: use Perl compatible regex

`-m` max-count, Stop reading a file after NUM matching lines.

And now for the regex:

`name:`: find the exact match

`\s*"`: Zero or more spaces leading up to and including an double quote

`\K`: This was the kicker for me. "resets the starting point of the reported match. Any previously consumed characters are no longer included in the final match" - basically tells the regex engine that the characters _before_ `\K` needs to be there in order to form a match, but it should only return the characters _after_ `\K` as the match. This is super handy! Is there a "reverse \K"?

`[^"]+`: One or more characters that are not a double quote. This basically means "Find the line that has a key called "name" and return all the characters after the first double quote and until the last double quote"

If you'd like to learn more about such grep powers, check out my free ebook [0]

What do you mean by "reverse \K"? Are you aware of lookarounds? Perhaps you meant positive lookahead?

    # match digits only if there is a semicolon afterwards
    $ echo '12; 42,31;100' | grep -oP '\d+(?=;)'
    12
    31

[0] https://learnbyexample.github.io/learn_gnugrep_ripgrep/intro...

In vim there is `\zs` and `\ze` where `\zs` is the `\K` equivalent in grep.

Basically

  :%s/hello \zsworld\ze out there/planet/g

would find all `hello world out there` and replace `world` to `planet`.

Consider this:

    grep -P 'start: (\d+) end'

"How do I make it print only the captured group with the number, not the whole line?" is a pretty common Stack Overflow question. The "\K" thing gets rid of the "start: " part, but what about " end"? That's were "reverse \K" would come in handy.

That's where lookarounds help:

    grep -oP 'start: \K\d+(?= end)'

`\K` is kinda similar to lookbehind (but not exactly same as it is not zero-width), and particularly helpful for variable length patterns.

If you need to process further, you can make use of `-r` option in `ripgrep` or move to other tools like sed, awk, perl, etc.

That's where ripgrep's -r/--replace flag comes in handy:

    $ echo 'foobar start: 123 end quuxbar' | rg 'start: ([0-9]+) end'
    foobar start: 123 end quuxbar
    $ echo 'foobar start: 123 end quuxbar' | rg 'start: ([0-9]+) end' -r '$1'
    foobar 123 quuxbar
    $ echo 'foobar start: 123 end quuxbar' | rg 'start: ([0-9]+) end' -or '$1'
    123

> Is there a "reverse \K"?

Look up lookahead and lookbehind (https://www.regular-expressions.info/lookaround.html, https://perldoc.perl.org/perlre#Extended-Patterns)

> all the characters after the first double quote and until the last double quote

Until the next double quote, not necessarily the last one.

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