The net round trip total power loss is usually well above 50%.
The net round trip total power loss is usually well above 50%.
* Suppose you can effectively and consistently get 40% of the energy you put into this kind of battery.
* Suppose you can make enough sand batteries to cover your overall power consumption (this is a big ask, but for the sake of discussion let's assume we can achieve this).
* Suppose that you have an energy source that's non-uniform across the day. For simplicity suppose that it produces 2N MegaWatts for 12 hours and 0 MegaWatts for 12 hours, i.e. N MegaWatts on average.
* Assume that electric power consumption, not including the batteries, is uniform across day and night (It isn't; it would actually be lower when power is generated if we're talking about solar).
* suppose we want a uniform power source when considering the batteries.
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Now, let delta be the fraction of our power output which we divert towards batteries, which are only charging during the 12 hours in which that is possible. Solving for uniformity,
fraction not diverted to batteries = fraction recovered from batteries
(1 - delta) = 40% \* delta
1 = 1.4 \* delta
delta = 1/1.4 = 5/7 ~= 0.7143
1-delta ~= 0.285
So, you get a power source that's uniform over the entire day at 0.285 * 2N = 0.55 * N MegaWatt, i.e. over half of your average power output of the unstable source.That's not great, but it's pretty damn good!