Edit: "A little" is inaccurate, the probability of the remaining lifetime being at least T is actually 25%[1]. And all this is assuming a "Lindy proportion" of 1 (which seems reasonable) and that no other information is known.

[1] Calculation: Lindy proportion 1 corresponds to a Pareto distribution with probability distribution function `a / x^(a+1)` where a = 2 and the range of x is [1, ∞). The cumulative distribution function is `1 - 1/x^a`. So the probability of the remaining lifetime being less than or equal to the observed lifetime is CDF(2) = 0.75.