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Comment by bakul | Hacker News Reader
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bakul
·
> So f[;x][y] is f[x;y].
f[y;x]
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avmich
·
Yes. And J has & to bind left or right argument to a dyad making it a monad - e.g. -&5 allows (-&5) 11 which evaluates to 6, while (5&-) 11 evaluates to _6 .
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