As you reach a state where almost all particles are in their maximum energy states (this is assuming there is one) you will slowly approach negative zero (which again you can never quite attain).
Statistical mechanics can be confusing at first.
In particular even with a quantum non-interacting gas with particle-in-a-box modes, the Hamiltonian is not bounded from above and there is no reason to expect a negative temperature, no?
There exist systems, like spin systems, where energy is bounded from above and so entropy decreases as you add energy, which is the definition of negative temperature... But I find it dubious that every system is such, unless I am missing something nonintuitive about say relativistic effects or so
> This is only possible if the number of high energy states is limited. For a system of ordinary (quantum or classical) particles such as atoms or dust, the number of high energy states is unlimited (particle momenta can in principle be increased indefinitely). Some systems, however [...], have a maximum amount of energy that they can hold, and as they approach that maximum energy their entropy actually begins to decrease.
In my (limited) understanding, it's somewhat like the phenomenon that a communication channel bit error rate over 0.5 actually results in less information loss (imagine a BER of 1: that's just a NOT gate).
If your energy states are limited, adding energy actual brings you closer to an ordered state (that of everything being in the highest state).
But, this is not a situation you get by simply heating something up with a blowtorch, no matter how hot it is.
(I’m not a physicist so I’m willing to be corrected, but this doesn’t jibe with my low level compulsory physics courses from uni :) )
For most normal systems, entropy increases with an addition of energy, and they have a positive coldness. Confusingly, the lower the entropy change, the less cold or hotter we would regard it: if you bring two systems into contact, they share energy to maximize their total entropy, so something which has low coldness = low entropy change will donate a lot of energy to something with a higher coldness = higher entropy change, the smaller negative will be balanced out by a larger positive.
You can extrapolate this to an infinite temperature, this would be an object with β = 0 or zero coldness, it can take or lose energy without changing its entropy at all. An example is an assembly of electron spins in a magnetic field, when 50% of them are aligned with and 50% are aligned against the magnetic field: this is the most entropic that the spin system could possibly be, so there is no way to increase it and to first order changes in energy do not decrease it. It has zero coldness or infinite temperature.
Add a little bit of energy and it is in the state where it actively wants to lose energy, putting more energy into the system requires aligning more of the spins along the magnetic field. This is a negative coldness, which is also regarded as a negative temperature by this T =1/(k β) formula.
Perhaps the correct measure is not temperature, but inverse temperature (i.e. 1/T)?
[1] https://www.popsci.com/article/science/ask-anything-whats-ho...
(sorry, can't provide anything beyond that level)
I mean that's the general upper limit on stuff in the universe: it eventually collapses into a black hole.
v ~= Sqrt( k_B * T / m) ~= constant * Sqrt(T)
(There is another constant in the formula that depends on what definition of mean you use, but it's safe to ignore it for this discussion.)
So if T is big enough, the result of this formula is faster than light.
But this formula is useful only for a not relativistic gas. Once the temperature is so big that relativistic effects are important, you must use another formula. (The other formula is more difficult to calculate, but when the temperature is low the result is almost identical to the formula I wrote.)
Temperature has no theoretical upper limit, but if it's high enough weird things can happen as described in a sibling comment. More details in https://en.wikipedia.org/wiki/Planck_units#Planck_temperatur...