e.g. if you have x and y in the environment as variables, and call your fexpr with (max x y) as the single argument called m: (myfexpr (max x y))

In haskell, m is not calculated (i.e. "max" is not run, nor x or y consulted) until "used". But the function doesn't "know" that it's max that's waiting to run, just that m is available if needed.

In a fexpr, you get something like a macro does, so you can see '(max x y) if you care to examine m, and you must call (eval m) to get the answer, but you could theoretically decide to do something else, like form a new expression if you walk m and make a decision based on the code itself (i.e. that it's a call to "max").