If the average person had a 1/80 chance to die each year, the average life expectancy would be 40 years.
Think about this another way. You have a gun with 80 chambers and 1 bullet. How many times on average can you point it at your head and pull the trigger before it goes off? Would you still argue 80 times? On average it is the last chamber?
https://en.wikipedia.org/wiki/Geometric_distribution
Your gun example has a uniform distribution between 1 and 80 with an expected value of roughly 40 if you don't spin the chamber each time between pulling the trigger. If you spin it each time, then it's again the geometric distribution and the expected value is 80.
If you don't spin the chamber between each time, then each time you pull the trigger the probability of dying at that round is not 1/80, the probability goes up and up at each round, it's only 1/80 on the first round.
The question is comparable to a gun with infinitely many chambers, each with a 1/80 chance of containing a bullet: How many times on average can you point it at your head and pull the trigger? The differences are that you have no guarantee that the first 80 chambers will contain exactly 1 bullet, that more than one chamber can contain a bullet, and that you can pull the trigger more than 80 times.
E = p/(1-p)
So pretty close to 80 years, no?
I guess it gets more complicated because you'd die of other reasons as you age so there's no point including the eventualities where you reached 120 for example... I guess it gets pretty complicated in the end...