EDIT: hmm, or a supplemental weight on the payload side, moving outward the right distance as the payload releases.
It seems like you'd generally want the non-payload rotating bits to vastly outmass the payload, so its release perturbs the whole system to the least amount possible. And then you use regenerative braking to reclaim the energy .
What I came up with was this: the launch arm has a second mass inside it, that will move (via centrifugal force) away from the center, in the same moment the payload is released.
Of course, just having two payloads launch in opposite direction as you propose maybe has much less implementation problems (though I wonder how you stop that second dummy payload in a way that does not cause an earthquake or explosion :)
> Although not shown in the previous figures, the circular mass accelerator structure 150 may comprise a second exit port directly opposite the exit port 115 to capture the counterweight 135 that is released simultaneously with the launch vehicle 105 to minimize an imbalance on the motor at the time of release. The counterweight 135 may be a solid material, or a liquid such as water.
The use of a liquid is a curious idea. Perhaps it could be dispersed in such a way as to spread the force of the counter weight being released across a wide surface area? Like a small explosive forces the liquid out in all directions?
According to this site [2] that's equivalent to around 200 kg of TNT. Even with the counterweight being mostly water, that's quite a lot of energy to disperse. How does one evenly spread out the water to a surface the size of a football field? Would that even be enough area to prevent a shock wave being reflected back at the launch equipment?
[1] https://calculator.academy/joule-calculator/#f1p1|f2p0
[2] https://www.convert-me.com/en/convert/energy/tntkg.html?u=tn...
* 5 metric tons TNT
* 1/3000 Little Boy atomic bomb
* 4 barrels of crude oil (!)
* Boil 2,300 gallons of water
* 0.25 mg of matter converted to energy
* Enough energy to melt two 11,000 kg iron counterweights, with 2 GJ left over
* A magnitude 3.7 earthquake [1]
[1] https://www.volcanodiscovery.com/earthquakes/energy.html
It's got a lower lever so the overall momentum might be low enough to make that recoverable. Maybe if it's 10% of the rocket's momentum, going into... yeah, it's hard to imagine that being recoverable but maybe it's just weights and that's good enough.
I'd love to see a real explanation.
Doubtful even if pointy. Water is way denser than atmosphere