Riesz Proves the Riesz Representation Theorem
nonagon.org
nonagon.org
The "kernel trick" from kernel SVMs only works because of the existence and uniqueness result from the RRT on the underlying Hilbert space.
The article is about representing continuous linear functionals on a space of continuous functions as signed measures (or Riemann-Stieltjes integrals). This has lots of applications in ergodic theory or representation theory (e.g. disintegration of measures).
This result is essentially unrelated to the result characterizing continuous linear functionals on Hilbert spaces. It is also much more difficult to prove (the result on Hilbert spaces is rather simple).
Thanks for the correction.
Isn't that the source with the proof described in the article as ungrokable?
All the writing I've read by Rudin is very precise. Sometimes a reader might want an intuitive understanding of what is going on, and for this after reading carefully take some time out, look back, and formulate some intuitive views. Right, in Rudin's books I've never seen a picture, but there is no law against drawing ones own pictures.
But for that subject, call it functional analysis, I also learned from Royden's Real Analysis, a little from each of several other books, and the lecture notes from the best course I ever had in school.
Overall, I liked learning from Rudin's books -- I'm glad to have such high quality math writing. But Halmos is my favorite author. And when they cover the same material, I like Royden better than Rudin. One of my main interests in that math is as background for probability, and for that my favorite author is Neveu.
Sorry about the OP: For me, the Riesz representation theorem is a very old topic; I covered it quite well in the past, don't want to go back, and am doing other things now.
For anyone who wants the Riesz theorem, in Rudin a nicely general version with a precise proof is on just a page or two with, say, a few more pages to get ready for the theorem itself.