A game with a windfall for a knowing few
boston.com
boston.com
A $2 Cash WinFall ticket allows you to pick a set of 6 distinct integers from the set {1..46}. The lottery commission then picks six distinct integers at random from the set {1..46}, effectively by drawing numbered balls without replacement from an urn. The payouts for May 9, 2011 were $24821 for a match-5 (a ticket that has 5 numbers in common with the set chosen by the lottery), $824 for a match-4, and $26 for a match-3 (http://goo.gl/gSTsF). It's easy to show that buying a ticket on that day had a positive expected value.
[Edit to show expected value calculation: According to http://www.masslottery.com/games/lottery/cash-winfall.html, the probability of a match-5 is 1/39028.41, the probability of match-4 is 1/800.58, and the probability of a match-3 is 1/47.40.
Then the expected value of a $2 ticket on May 9, 2011 was $24821/39028.41 + $824/800.58 + $26/47.40 = $2.21.]
$10,000 will buy 2,000 [Edit: oops, actually 5,000. Also fixed in what follows] Cash WinFall tickets. When you can only buy a few tickets in a lottery like this, the distribution of the numbers on your tickets greatly affects your chances of coming out ahead. For instance, if you buy 5,000 copies of the ticket {1,2,3,4,5,6}, your chances of coming out ahead are much worse than if you buy 5,000 tickets with a bunch of different numbers, although of course your expected winnings are the same in each case, provided no one hits the jackpot.
It's actually an open problem to create a set of 5,000 Cash WinFall tickets that maximize your chances of coming out ahead. Indeed, a Boston-area employer (that's still hiring!) posted a hiring problem based on this for several years.
If the total prizes won for any drawing, exceed 200% of the net sales for that drawing the prize amounts will be based upon a formula detailed in the Rules and Regulations or Administrative Bulletins issued thereunder.
which has to add a little FUD into the thinking.
More generally, this is an example of how simple changes (the rolldown) can have surprising consequences. TBQH I'm surprised the lottery operators aren't just keeping the surplus funds rather than doing a "roll down".
This particular scheme pays out most of the money to a select few, though, which defeats the point.
Does it? To me the only point of a lottery is for the operator to make a predictable profit; that predictability is why governments like them so much.
Who wins the jackpot is pretty close to irrelevant.
(Yes, I'm pretty sure that's how this will be reported in local media.)
Illinois actually has true raffles a few times a year and they have always sold out before the drawing date.
I think Massachusetts would be likely to earn more money by being able to advertise a much, much larger jackpot and losing these "rollup day" "gamblers" (when your mathematical theoretical return is so far above 100%, I hesitate to call it gambling) but apparently they have some incentive to keep things the way they are (do lottery officials have relatives or buddies who are among those gaming the system?) because they've let this go on so long.
By knowing the total tickets Ntt each time, Pjh can be estimated easily: Pjh=1-(1-P6) Ntt Lottery P6 is the probability of matching 6 numbers. In the case of the WINFall lottery, P6=1/13,983,816. The total tickets Ntt each time can be estimated by its samples and their probabilities. The WINFall lottery has 4 samples, matching 6 numbers N6, matching 5 N5, matching 4 N4 and matching 3 N3 respectively. N3 is the largest sample of the WINFall lottery. As far as we have four samples in hand: N6 N5 N4 and N3, we use N3 to calculate the total tickets. Because the more sample are there, the small differences we have (Statistics Accuracy). The Ntt is: Ntt=N3/P3 P3 is the probability of matching 3 numbers. In the case of lottery WINFall, P3=1/57.
To win is really practical.
However, government should make more money than buyers even following the abave rule.
if they were truly sophisticated they would enjoy it just the same whoever it went to.