Newtonian physics IS deterministic (sorry Norton) (2017)
blog.gruffdavies.com
blog.gruffdavies.com
The fact that the author quibbles about units, when they've failed to notice the Norton took `g=1`, makes it seem as if they're not familiar with conventions in mathematical physics. The addition of a constant `k` adds no value other than converting between units, which aren't of interest here other than as a bookkeeping mechanism, because we're not dealing with any numerical quantities.
I wouldn't say "that's all." If it actually does admit nondeterministic solutions (I am not convinced that there is no property or axiom buried in the formalism that forbids this case somehow), then the next question is, does quantum mechanics, which implies classical mechanics, admit nondeterministic solutions? If not (wave mechanics has a way of ignoring weird stuff when it only happens at a point), that would make quantum mechanics a consequence of determinism, a fairly shocking possibility.
//This is where Norton gets tricky with us. He posits another solution to the equation ...
Norton didn't posit this as a solution, it is a solution.
//This is baffling. It’s bizarre to stitch two different solutions to an equation
Norton never stitches together two solutions. I don't know if Dr. Davies is unfamiliar with a function defined using a case statement, but there's nothing Frankensteinish about it.
//but in fact the top equation is not Newtonian at the apex (clearly since it moves despite the absence of a force there).
Alas, Dr. Davies has missed the biggest delight of Norton's Dome! The ball can nondeterministically roll off of Norton's dome and yet still obey all of Newton's laws :-). It sure looks like it wouldn't be--after all, how can the ball start to move in absense of a force?
But at time t=T, the ball isn't moving yet. Its not even accelerating yet. So at time t=T its obeying Newton's laws. An at every time before and after that it also obeys Newton's laws.
That's not a resolution to the philosophical issue, but it could help us come up with one, given that some other systems are so much simpler but have the same property.
So, if anyone wants to think about this, you can think about x''(x) = -x^2 just as productively, without the extra complexity.
> [...] I always thought the only necessary initial conditions were position and velocity or position and momentum, a case is presented where that doesn't happen. It's implied in the exposition of Hamiltonian mechanics that those are the only variables that describe a particle at a point in time, and that's how it is treated in computational simulations.
There's usually an implicit assumption that the functions you're dealing with are sufficiently smooth (differentiable as much as you want at all points). In Norton's dome, the derivative of the height of the surface (the slope) does not exist at r=0 because d/dr sqrt(r) = 1/(2sqrt(r)).
For example, Black-Scholes is complete nonsense [1], but the C implementation is pretty easy to parse [2]. Yes, the code is 100 lines longer, but just like in programming, you'd just use it by name.
1. https://wikimedia.org/api/rest_v1/media/math/render/svg/d856...
2. https://gist.github.com/codeslinger/472083/0acc95f745def15a3...
[1] https://mitpress.mit.edu/books/structure-and-interpretation-...
https://en.wikipedia.org/wiki/Black-Scholes_equation
That in turn might not be easily understandable either, but it's written in terms of well-known concepts that they teach in math classes. You can get textbooks about that stuff and all that sort of thing. At the end of the day, making sense of it will take a level of mental effort comparable (not by coincidence) to taking a couple of years of math classes (starting from basic calculus) and doing all the assignments. Making the equations look more like code won't help with that. It's about developing understanding and facility with the mathematical ideas.
It looks there's a paper related to the topic.