This will probably give the wrong answer for some integer. I have tried something similar in Java. Since it was three years ago my memory is a little hazy. I was working on a parallelizing compiler written in Java (but not for Java) and I saw that the other programmers had used a method similar to yours, it used log anyway. I knew about #9 and #10 and worried that their method was potentially wrong (and also inefficient). To check if it was wrong I coded up something that compared the log-floating point method against #10 for all non-negative integers and the log-floating point method gave the wrong answer for one value (out of 2 billion).

That was Java and your example is in Python, there could be some difference. If you try and compare in Python, please tell us the result.