Hacker News Reader

>> but I didn’t see the method I expected to find: Use the Taylor series for f(x) = e^x around f(0) to compute e = f(1)

Is that the one where e = 1 + 1/1! + 1/2! + 1/3! + ... ?

Steve Wozniak used that method to compute several thousand digits of e on an Apple II back in the day. I think Byte ran an article on it.

Super easy because each term is just the previous term divided by N.

Yes, that's the Taylor series.

It's included (he calls it Newton's), and he follows it with the even better Brother's.

Yes, the Taylor series converges very quickly, but for some reason the author insists on only using the problem that originally introduced Bernoulli and Euler to the number e.

The author not only included Taylor's (Newton's) but the superior Brother's.

They did. They called it Newton's series