Ergodicity, What's It Mean
avoidboringpeople.substack.com
avoidboringpeople.substack.com
Who here would take a bet where there's a 95% chance of losing their home and their well paying job, for a 5% chance of becoming a billionaire? I sure wouldn't.
My take on this: don't stop at averages, look at the whole distribution.
As for what a realistic bet would look like (you're founding a startup or something), I believe the expectation is often not much greater than 1, so one does not simply found 100 startups and distribute the income of the 5 successful ones to everyone else. (And even if it is, the people capable of founding startups often have steadier, though less impressive, means of increasing their wealth. Startups are often founded for reasons other than wealth, after all.)
I think it's uncharitable to say the article would be easier to understand if it didn't use the language of ergodicity. Its explicit goal is to show how non-ergodicity leads to an example like yours.
So of course your comment seems easier to understand. But that's because you're just saying different distributions can be parameterized by the same mean. Ergodicity is about a lot more than that, and the language of ergodicity was the entire exercise here.
But their application to non-standard-mechanical things is very confusing.
Of course wealth is not ergodic. Ergodicity would mean that the distribution is always the same. Every point in time would be identical to every other point in time and growth would be impossible.
Someone new to ergodic theory may understand from that article that if wealth was ergodic the average for every trajectory would increase like the average for the entire system. But that doesn’t make sense.
More specifically:
- The distribution of outcomes at certain points of interest in time (like the valuation of my company when I intend to sell it).
- The probability that we cross a catastrophic threshold at some point (like bankruptcy).
Time average is a terrible metric to estimate those things. Heck, I'm not sure it can measure anything of interest, besides our own mistaken intuitions. It should probably be called something like "time average fallacy".
It seems like you think the problem here is too unsophisticated for ergodic theory or something. Which, fine sure. But this isn't an article intended to teach you about betting. It's an article intended to teach you about ergodicity, using betting as a toy example. The author isn't trying to introduce the best way to analyze betting strategies, they're trying to show what non-ergodicity is. And I think they basically succeed.
Just meet the article where it is, for its intended usage.
That's a very special case. For everything else (that is, non-ergotic processes), your time average is crap, and you must look at the distribution of outcomes directly. Even the ensemble average is not enough. Averages are crap at visualising skewed distributions. For those you want the median, the quartiles, sometimes even the percentiles.
---
To be honest, this "ergotic theory" shows signs of snake oil. The definition of ergodicity itself is dead simple, so it's pretty easy to evaluate. What seems pretty clear is that ergodic processes are the exception. And a pretty uninteresting one at that, since it's a class of processes that people will have good intuitions about.
It would then seem that ergodic theory is more interested in the non ergodic processes (the very point of this blog post is to warn us about them). That is, processes that lack some property —the general case. And surprise, since the time average and ensemble averages are different, and you only care about the ensemble average (well, the ensemble distribution really), the time average won't help you. Be afraid, or lose your assets.
That's why I see snake oil: what works on non-ergodic processes will also work on the ergodic ones. Unless you need to make a split second decision using your intuition (which while inadvisable is safer with ergodic processes), there's no need to make the distinction at all. Just analyse your process without without assuming it will be ergodic, the results will be applicable even if it is.
> To be honest, this "ergotic theory" shows signs of snake oil.
lol. Alright, I’m checking out of the discussion when a major subfield of mathematics is described as snake oil.
I did not mention those stupid coin tosses, where did you get the impression I was talking about those specifically?
> a major subfield of mathematics is described as snake oil.
I did not say it was snake oil, just that it shows signs of being such. Then I described those signs. If you have counter arguments or pointers to such, I'd be happy to read them. I'd rather lose an argument and learn something than stay ignorant.
This intro doesn't get to the depths of the issue. https://www.nature.com/articles/s41567-019-0732-0, by one of the pioneers of the "egondocity economics" is very nice for both going over the math and the academic history of the error.
Given the illustrious history of statistical mechanics into Modern probability theory, information theory, theoretical computer science, etc., it's a real shame Econonomics is still stuck with this bad math.
https://aeon.co/ideas/how-ergodicity-reimagines-economics-fo... the pop-sci narrative here really doesn't seem that much an exaggeration. The way non-ergonomics fixes the math and confirms some real-world intuitions is quite profound. And certainly there is a lot to critique with orthodox economics' math. (See https://themountaingoateconomics.com/ for another example.)
Are you calling “bad math” the expected utility theory developed by von Neumann (et al.)? He knew one thing or two about ergodicity, information theory, computer science, etc.
I read https://en.wikipedia.org/wiki/Von_Neumann%E2%80%93Morgenster..., And there's no notion of time let alone non-ergoticity in the formula. I am not familiar of with the rest of its book, but I wouldn't be surprise if it's similarly fine, building a theory similarly of rich theorems about very simple models.
If so, the problem isn't Von Neumann's math then, even if the general aim of the endever was misinspired by Bernoulli's primitive notions. The problem would be all the math cargo culters in economics who constantly try to the premise premises of math theorems as if they were broad social laws.
I mean don't get me wrong, I am no fan of Von Neumannn's politics, but obviously I am not going to fight his pure math.
If you're a reasonable person instead, you recognise that probabilities instead describe a state of partial information (that is, probability is in the mind), and the "ensemble average" really comes from a probability distribution we can compute with bog standard probabilistic counterfactual reasoning, not by actually hopping universes.
My, the abstract didn't prepare me for this.
For a coin toss example like this, the distribution of heads and tails in each trial is ergodic. The distribution of earnings is not. This isn't because of any difference between time average versus ensemble average. It's because the probability of winning each toss is time invariant but the amount you stand to win or lose isn't because it's a function of both the probability of winning and your current bankroll, and current bankroll is not time invariant.
Although, ironically, because of the numbers he picked, all bankrolls tend to zero eventually, so over a large enough number of trials, wealth eventually becomes an ergodic process as well. Graphing out his scenario over more trials gives a sort of heat death of the universe plot, where some players stay alive longer than others, but in the long run, the enemy always wins.
It's funny how you say "the author made it a bit more complicated than it needs to be" and then proceed to explain it with even more jargon ("Ergodicity for a stochastic process just means the joint distribution of random variables that make up the sample space is time invariant").
The process of simply flipping coins, even a biased coin, does correspond to a dynamic system where the space is all infinite sequences of heads and tails, the invariant measure is the joint probability, and the operator is the left-shift (i.e. if you sample 1 series of coin flips and throw away the first result you still end up with a sample of the same distribution).
But this doesn't translate at all to their proposed scenario of starting everyone at 1 and letting the results diverge from there.
A given point has current wealth as it's level and moves randomly up and down in that level according to a process that's random.
https://en.wikipedia.org/wiki/Dynamical_system https://en.wikipedia.org/wiki/Random_dynamical_system
I suppose you can make it fit the definition for the random dynamical system, though in that case the underlying dynamical system is ergodic.
This's got nothing to do with ergodic theory though, but feel free to use that word in whatever weird distorted way you like, I literally can't seem to stop you.
1. A state space X
2. An evolution map f: X -> X
3. A measure \mu on X, preserved by f (such that f_*\mu = \mu) and where \mu(X) = 1.
To represent a series of i.i.d. random variables you can typically just represent them as a sequence of values with a joint probability distribution as the invariant measure.
If you've got a space X of such sequence you can also add the current value to it to get IR x X, with a map f: (x,t) -> x * 1.5 if t[0] is heads & x * 0.6 otherwise. But you'll have to tell me it's invariant measure because I can't come up with one.
non-ergodic example: Russian roulette. If you play russian roulette 1e6 times in a row, you will always be dead at the end. If 1e6 people play Russian roulette at the same time, 1e6*(5/6) people will be alive at the end, and only 1e6/6 people will be dead.
The situation the article explores was interesting, but made the jump to something mathematically complex before I sunk my teeth into the fundamental bit.
If you added some effects on what kind of gambles are available to players at different levels, you can create several different attractor states.
Ergodicity is a nice property of models like molecules of gas bouncing around a room, which means that statistical mechanics is practical. If one percent of the molecules tended to end up with all the kinetic energy, while the other molecules gradually one by one reached a complete standstill, then statistical mechanics wouldn't work.
Since the very simple process shown in the article doesn't have this property, it means some familiar statistical tools can't be used naively with these models, or to extrapolate a little bit, to any model of any human activity that tends to these kinds of capturing, fixed-point, attractor outcomes.
So in fact regardless of the initial run of luck, every player still goes to zero with probability one. The youtube video that another commenter linked to actually explains the 40% and 50% example much better.
Made it click straight away for me.
This happens to not show after only 100 trials just because some tiny number of people get really lucky and draw up the ensemble average, but if you keep going, somewhere between 200 and 500 trials, the ensemble average pretty quickly drops below the starting average wealth and stays there, asymptotically approaching 0.
There is one assymmetry at the zero point (assuming people can’t recover from bankruptcy by borrowing another dollar) but that’s easily fixed by adding a simple bet strategy e.g “bet at most 1/10 your bankroll on each bet”.
This is wrong. The bet as described has a positive EV and the time average for a single player tends to zero as the bet is repeated.
> There is one assymmetry at the zero point (assuming people can’t recover from bankruptcy by borrowing another dollar) ...
The result is not due to zero being an absorbing value. In the setup you can go arbitrarily small and come back without issue. The result is the same.
This is a bet of 0.4.
With 2.0 odds the payout would be 0.8, and here it is 0.9? That looks like odds over 2.0 for 50/50 chance.
So the individual bet is positive EV but the EV of an infinite sequence of such bets is still zero and that’s without the zero limit? There is just nothing in the article that begins to explain how that works. Maybe the video is better
The median outcome is indeed negative, for the reason you give. But the mean outcome is positive, because some players become exceedingly rich.
You can try it at home, here's some Julia which runs it over 1M people, each with 1K flips:
using Distributions
n = 1000
d = Binomial(n, 0.5)
to_wealth(heads) = 1.5^heads * 0.6^(n - heads)
rand(d, 1_000_000) .|> to_wealth |> mean
You can keep running that, it's above 1 almost all the time.To look at this another way — would you take the other side of the bet? Someone on average has to be making money, and the other side is clearly losing money.
import numpy as np
import pandas as pd
n_subjects = 100
n_trials = 1000
start = 10.0
win = 1.5
loss = 0.6
prob = 0.5
results = np.ones((n_trials, n_subjects)) * start
for trial in range(1, n_trials):
wins = np.random.binomial(1, prob, n_subjects) == 1
results[trial, wins] = results[trial - 1, wins] * win
results[trial, ~wins] = results[trial - 1, ~wins] * loss
ax = pd.DataFrame(results).plot(legend=False, figsize=(18,10), logy=True, linewidth=0.5)
ax.plot(results.mean(axis=1), color='red', lw=2, linestyle='--')
The mean always trends to 0 and every single player eventually loses. There are never any winners at all past around 500 trials or so. Not sure how you're getting a different result as I have never used Julia and can't tell what your code is doing (except apparently something different).Looking at the Julia code, I think what he is doing wrong is making all wins worth $.50 and all losses worth $.40, but the bet computes a win or loss based on your current wealth, not your starting wealth. His formula would work if you were always betting $1 no matter what your bankroll was, but that isn't what the actual post stipulates.
If you don't trust the Julia code, try running with the same parameters in Python.
My code is right up there and you can run it. You can even just run the OP's notebook that he provided but increase the number of trials. Change the "num_flips_per_sim" parameter he provides in cell 6 to anything over 500 and you will always get sum(count_lose_capital) == everyone.
The appropriate response to that is introspection, not repetition.
More precisely there is a finite time after which no-one ever passes above $0.0000000000000001.
That is a mathematical theorem.
This doesn’t depend on the number of test subjects, and you can add as many zeroes as you want.
Therefore in the long run the mean outcome is 0.
Forgive me if I have misinterpreted what you are are trying to say.
Edit: I’ve just realized that I have indeed missed your point.
It’s a mathematical theorem. (I would be curious to see a proof of your theorem, by the way.)
t=0 mean(w) = 1
t=1 mean(w) = 1/2*1.5 + 1/2*0.6 = 1.05
t=2 mean(w) = 1/4*1.5*1.5 + 1/2*1.5*0.6 + 1/4*0.6*0.6 = 1.1025
....
t mean(w) = 1.05^t
Don’t you agree?As for the proof of my theorem, By taking logarithms, the process becomes an additive random walk with negative drift (log 1.6 + log 0.5 < 0). This is well known to converge to negative infinity almost surely. After exponentiating to undo the logarithm, this is exactly the statement I made.
It does not matter how many test subjects there are ( as long as there’s finitely many) because, informally speaking , you can just wait for each of them to become irrevocably bankrupt in turn.
- for a fixed sample size we can find a time large enough that the probability of the sample mean being above $1 is as low as we want
- for a fixed time we can find a sample size large enough that the probability of the sample mean being below $1 is as low as we want
- when both the sample size and the horizon grow without limit which effect dominates will depend on how we make it happen
Adding "almost surely" to "everyone goes bankrupt and will never recover" or "there is a finite time after which no-one ever passes above $0.0000000000000001" is a subtle change but it's enough to allow for someone to go to infinity with infinitesimal probability.
This is why the distribution mean can grow exponentially, it wouldn't be possible if the everyone and no-one in those quotes were strictly true.
Just to confirm, I am using 'almost surely' in the technical sense, which means 'with probability 1.'
Consider the following statement:
If you keep flipping a fair coin every day, it is almost sure that after some day you will have gotten a tails.
This is the same 'almost surely' that I am referring to.
The point was that you didn't specify "almost surely" previously, that's why I asked for a proof to understand what did you mean exactly when you said that "everyone goes bankrupt and will never recover" and "or "there is a finite time after which no-one ever passes above $0.0000000000000001".
The mean of a random variable that is close to zero is close to zero, the mean of a random variable that is almost surely close to zero can be anything.
After 500 trials, you need 279 heads to stay above $1 net wealth. 1.5^278 + 0.6^222 = 0.50 and 1.5^279 + 0.6^221 = 1.26, so that's your breakeven point. The probability of getting at least 279 heads in 500 coin flips is 0.005364, so with 1,000 participants, you expect to see about 5 still above water.
At 1000 trials, the breakeven point becomes 558 and the probability of getting at least that many heads in 1000 flips is 0.00013614. So the expected number of people who stay above water in a pool of 1000 participants is 0. Out of 1,000,000, it is 13, so you're right, there are some, but at that point it's not nearly enough and we're not sampling the ones whose wealth is enough to actually bring the mean back up, so it keeps trending to 0 in any sample of a practical trial size.
This is a pretty interesting property of this problem, really. It's not related to ergodicity, but just the relative proportion of probability mass represented by above 1 and below one itself trending asymptotically toward 0 even though the analytical expectation trends toward infinity. I don't know that there is even a word for that, but seemingly which of those moves faster toward its limit would determine what sample ensemble average you really see when the number of realized states is far less than the number of possible states.
This probably has some implications for Pascal's Mugger type problems in decision theory. If some course of action has potentially infinite future payoff and destroys expected utility calculations because of that, but the expected number of possible universes in which a positive outcome happens at all trends toward 0 faster than the expectation trends toward infinity, that gives a decision rule. In this specific case, don't take this bet, at least not in an indefinitely repeating form.
A shorter run (say 100 steps) would be more likely to capture enough realisations to produce a reasonable estimate. You could assess this behaviour yourself, for very low step numbers, by calculating the variability in a sampled ensemble average, relative to the exhaustive (i.e. true) ensemble average.
This particular problem is another consequence of the properties dynamical system being examined, but not quite the same as the issues caused by its non-ergodicity.
import numpy as np
import itertools
from matplotlib import pyplot as plt
def ensemble_mean(outcomes):
# Assume we are given a (K, T) array of outcomes, and compute the ensemble average
# for T+1 time steps, starting with 1 wealth.
K, T = outcomes.shape
X = np.ones((K, T+1), dtype=np.float64)
X[:, 1:] = np.where(outcomes, 1.5, 0.6)
Z = np.cumprod(X, axis=1)
return Z.mean(axis=0)
time_steps = 20
all_outcomes = np.array(list(itertools.product([0, 1], repeat=time_steps-1)))
exhaustive_mean = ensemble_mean(all_outcomes)
ensemble_size = 100
ensemble_samples = 10000
ensemble_means = np.zeros((time_steps, ensemble_samples))
for i in range(ensemble_samples):
print(i)
# generate ensembles as though we were sampling (i.e. with replacement)
J = np.random.choice(all_outcomes.shape[0], size=ensemble_size, replace=True)
ensemble_means[:, i] = ensemble_mean(all_outcomes[J, :])
plt.hist(ensemble_means[-1], bins=1000, histtype='step')
plt.axvline(exhaustive_mean[-1])
plt.title("Modal sampled ensemble mean is below true ensemble mean")
plt.show()Sounds like a good strategy whether in Vegas or Wall Street.
n_subjects = 1000
n_trials = 100
After 2 tosses, the probable outcomes are 25% 2.25, 50% .9, and 25% .36, giving an expected value of 1.1025 interestingly enough. Overall a 75% chance of losing money.
For a bet of $X, the expected value is: (1.5 * X) * 0.5 + (0.6 * X) * 0.5 => 1.05 * X. The ensemble average per round is positive (1.05) and over multiple rounds smoothly tends to infinity with the number of bets. (Definition here: https://en.wikipedia.org/wiki/Expected_value).
The time average for any specific person betting in this game is 0.95 * X (for the reasons you mention) and tends to zero with the number of bets.
So let's go through a few specifics of your comment:
> He actually picked bad numbers. That is a losing bet even on average.
The point of this article is that "on average" is trickier than people tend to assume. There are different ways of taking averages. If you do the expected value calculation and get a positive number, you might (as other comments have said explicitly) expect that a participant repeatedly engaging such a bet would have his wealth trend toward infinity. But, they are wrong (as shown in the article).
> This happens to not show after only 100 trials just because some tiny number of people get really lucky and draw up the ensemble average, but if you keep going, somewhere between 200 and 500 trials, the ensemble average pretty quickly drops below the starting average wealth and stays there, asymptotically approaching 0.
The ensemble average is positive and monotonically increases w/ the number of rounds of betting.
But I can also clearly see that never actually happens, and I do think I can explain it. The measure of people with any positive expected return at all after a large enough number of trials is so small that they eventually drop out of any actual simulation just because nobody ever gets that lucky, even though theoretically it is possible. You eventually reach a point after a large enough of trials (apparently about 500) where if anybody at all was actually hitting the 400+ heads out of 500 trials requires to still be above water, enough of them would be so fabulously wealthy that they'd draw up the entire average. But the probability of these trials ever happening is so low that we can run simulations for thousands of years and never see it happen, so what we see instead is nothing but common cases. Everyone after 500 trials is overwhelmingly within +/- 50 of 250 heads and 250 tails, and if you're in that range, you're a loser.
It also may be the case that the way these pseudorandom number generators work makes it completely impossible to ever see 400 heads out of 500 trials no matter how many simulations you run since they aren't actually random, but even if they were, practically speaking, I wouldn't be the least bit surprised if an any trial ever run of 500 consecutive fair coin tosses, nobody for as long as humans have existed has ever hit 400+ heads. If you try to analytically compute the probability and store it in a floating point number, it just rounds to 0 because we can't store a probability that low.
This becomes very large as the number of trials increases (likely approximately exponential)
People mistakenly think that if their investment made 50% and then lost 50% that they broken even, but they're actually down 25% (1.5*0.5=0.75). However, if you invest $100 and make 50%, then invest a second $100 and lose 50%, you do indeed break even.
When OP stated that the bet has a positive EV, it's for a flat $1 bet. Indeed, if you always bet $1 (or any fixed amount), it does have a positive return of $+0.05, and you should take the bet.
It's only when you change it from a $1 bet amount to an "entire bankroll" amount that you're looking at a geometric mean of 0.949 return per bet. That number is simply the geometric mean of the two possible returns, 1.5 and 0.6.
So the actual EV is sqrt(1.5*0.6)-1.00 = $-0.051 per bet (normalized to $1.00).
I don't understand the point this article is trying to make about anything else. The entire effect here is explained either by misstating the problem or by using the wrong type of mean for the EV calculation.
The idea that some lucky people will make money while the rest lose is explained by simple luck. Run the simulation longer and they will all lose out to the law of large numbers.
My intuition for it is like a particular kind of spread out mixing. Imagine a giant bowl with a bunch of crazy high powered pinball bumpers [0] at the bottom, randomly jostling the pinballs around, sometimes kicking them out where they started, but they always come back eventually.
If you roll a ball into it, it doesn't matter where you start. It'll get lost in the mix eventually. (it "mixes" sufficiently).
And no matter where you start, those high powered bumpers will eventually happen to kick a pinball all the way out there again, given long enough. (The "mixing" spreads things out sufficiently and occasionally sends things all the way to any point in the bowl).
By contrast, a bowl that's just high friction, where everything ends up stopped at the bottom wouldn't work, even though it makes it not matter where you started, because it doesn't "spread." It just sinks things to the same spot. An inverted bowl/a dome wouldn't work because starting on opposite sides means you'll just roll away from each other and never come together (no "mixing" at all). A bowl without bumpers would have you coming back where you started, but not "mixing" around to all the other spots.
You need both elements. It has to not matter where you started specifically by getting back to where anyone started.
Rereading my comment now, it really does come off as "a monad is like a burrito," doesn't it. But screw it, I'll hit post and maybe it helps somebody.
[0] This kind of bumper: https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcQa3gvh...
I'm also happy for the link to "a monad is like a burrito"!
If you grok this, everything else is technical detail and window dressing.
This does not mean that you shouldn't play a game with positive expected value. Expected value is still the salient framework with which you should judge risk. It just means that the size of your bet needs to be considered in conjunction with your total capital, not just whether any individual bet is more likely to win than lose.
The author states this seems to not be well known in finance, but in point of fact this is very well known in both literature and practice. A trading strategy with positive expected value has additional considerations before you execute on it, including your total capital and liquidity.
For what it's worth, my takeaway was that the "paradox" is that we aren't accounting for the nonlinear utility of money. Therefore the exponentially unlikely probabilities of winning quadrillions of dollars have exponentially large weights. But a quadrillion dollars isn't a million times more useful to me than a billion dollars. So if you account for that saturation effect and take the expected utility instead, the "paradox" goes away.
here I attach a mini program where I show that of course the gini coefficient in the group growth (in this case the yield is always negative but total wealth of group constant): https://pastebin.com/L5sSM09V
> Everyone starts with $1, gets 50% profit if they win, and pays 40% of their bet if they lose.
From the wealth-over-time graph, it looks like the bet is sized such that it's always 100% of what you have (per some trajectories going as small as 10^-7).
My read is that while each individual bet looks good in isolation, the fact is that one win and one loss puts you in the red overall -- when dealing with this iterated experiment you want to look not at E[X] = 0.05, but at E[log(X)] = -0.05 to get a sense for how your assets evolve each round.
For some intuition: if you win once and lose once, your net result is 1.5 * 0.6 = 0.9, so you've lost 10% of your starting money.
Suppose instead of betting all your money every round, you instead decide to bet 10 cents each time. Now, instead of being essentially guaranteed long-term ruin, you can and most likely will be able to continue making money indefinitely. (In fact, your chance of ever dipping below, say, $0.50 is finite even when extending your rounds played arbitrarily.)
The Kelly Criterion for this scenario actually dictates that you should bet 25% of your money each round. Using this betting strategy, somewhere around 70% of people end up making money off this game when run for 100 rounds (1% end up ending up with a respectable $25 or more, while about as many end up with <$0.15). You even have an opportunity for redemption -- when we drag out the horizon to 5000 rounds played, somewhere around 90% of individuals become billionaires, even as 30% of people were behind after 100 rounds (so 2/3 of those redeemed themselves).
On the other hand, with the all-or-nothing solution outlined in the article, about 13% of the population coming out ahead (around 1% of the population gets really rich, ending up with >$200, while more than half end up with less than a penny). Meanwhile, the odds get worse as the game goes on, as at just 500 rounds, >80% of players have been reduced to less than a penny.
That's a long-winded way of saying that the amount you bet is really important.
import random
l = 0.33
w = 0.5
c = 100
m = 1000
p = {k: c for k in range(m)}
n = 1000
for k in range(n):
for j in range(m):
if random.choice([0,1]):
p[j] += (w * p[j])
else:
p[j] -= (l * p[j])
print(sum([p[k] for k in p]) / len(p))
print(sum(1 for k in p if p[k] > c) / len(p))
I wrote this up quickly so there might be an error, but under your stated parameters the average wealth increases over time and most people end up wealthier than they started. Specifically, the number of people who will be wealthier at the end seems to converge to somewhere between 57-60%.NB: This assumes you bet your entire capital each round instead of a constant bet size. In the presence of non-ergodicity you wouldn't want to do this, but that just means it's an even stronger result that most people come out ahead.
In fact 33% happens to be the maximum loss percentage this system (win rate, win percentage, bet = total capital) can tolerate while still exhibiting higher wealth for most players over time :)
Perhaps we should find a tax rule which makes wealth ergodic.
IFF implemented globally, would you truly argue this disincentivizes creation of wealth? Add inflation and exchange rate adjustments and I honestly don't buy that argument anymore.
NOW, will you have selfish actors trying to game the system and evade these taxes through all means possible? Yes, but that's why I think anyone who supports the protection of private property through state violence and democracy at the same time needs to do some heavy gymnastics to justify tax evasion and dynasty enabling tax policies (i.e., anything that doesn't at least do the 100% inheritance/gift tax bit). And of course you'd need to implement it either globally or at least in economic powerhouse blocks like EU+US+Canada.
For example, a well-known issue with open source data infrastructure is that it often has much lower performance and efficiency than equivalent proprietary software. There are many dis-incentives in the open source ecosystem to producing software that is highly performant and efficient, not the least of which is development complexity and sophistication level required to contribute. Open source developers do not pay the operational cost of wasteful data infrastructure but they do pay the cost of their time, and prioritize accordingly. Proprietary data infrastructure is explicitly motivated by wealth incentives to be highly efficient, which is why companies invest in it even though open source equivalents exists.
The relative wastefulness of open source in terms of computing resources is increasingly perceived as bad for the environment, so it isn't just a money motivation. Incentives are a powerful thing and it is evident that open source lacks incentives to produce some important outcomes.
Maybe it’s $1 billion, after which you hit a ceiling function or wealth becomes ergodic, and you earn a badge that says “you won” (in the context of this society).
If you earn such a badge, society would call on you for advise (if you are a non-inheritor).
Did you consider the case where A works twice as hard as B and ends up with twice the wealth of B?
Yes, the latter is a leftist boogieman. But the non-ergodicity of wealth is really scary! We got along fine pre agriculture (little wealth differences), and then with wars and famines to reset, but surely we banning private school is better than more of those?!
Keep in mind non-ergodicity is also good. Socialized infrastructure like public transit for example:
- The risk / lack of extractive fees to make profitability makes it impossible to do well privately
- The benefits of pooled risk apply to even the richest people, who might with conventional econ think they are stuck at best with a noblesse oblige.
Agricultural, colonialism, and industrialization are massive qualitative shifts that non-ergodic models also do better justice.
If you've heard of Murphy's Law, you probably already understand the principle behind ergodicity.
"If there's more than one way to do a job and one of those ways will end in disaster, then somebody will do it that way."
When you increase the number of people doing something, the number of opportunities for that somebody to do it the wrong way goes up. These are the outliers versus the normal state of affairs. These don't have to be positive or even negative, simply improbable.
Given enough players for a lottery, there will be a winner, but there will also be people that randomly get linear sequences of numbers, all primes, etc.
Why this is coming from a throwaway is that this occurs for everything in life, including, for example, schools and police shootings.
These are extremely outlying events when given the absolute number of interactions between students and police. The ergodic space allows for these to occur, and so they do, eventually.
The problem is when people start taking infrequent outlying events as the norm rather than outlying properties of the system itself.
If you give 800,000 cops guns and send them out to interact with the public tens of times per day, they will eventually shoot someone they shouldn't have. This is a normal part of the space but isn't probabilistically normal. The normal state of affairs is that they don't shoot anyone. In the rare case that they do shoot someone, it's generally because they are being shot at.
Equally, if 100 million citizens have guns, eventually one will end up in the hand of one of approximately 7.5 million (probabalistically) male high school students that is willing to use it against other students. This too is part of the ergodic space, but isn't probablistically normal. The normal state of affairs is that school shootings don't happen. The normal state of affairs is that bullied and/or mentally ill students don't seek violent retribution against their classmates.
These are simultaneously improbable and probable events. We know that they occur, but we know that they occur infrequently. Inevitably, given enough rolls of the dice, circumstances conspire to enable extremely improbable events to occur, but these should always be seen as the opposite of the norm.
However, if you detach yourself from a distraction you would note that capitalist economies are not like independent bets at all, and much of the accumulation is due to confiscation, occupation, sabotage, undercutting to drive competitors out, propaganda (advertising), etc. - directly or by manipulating the government.