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Nah. he should stop after the tenth (second). iterate over (0,1) , but sing (1,10) or i+1. excellent jokes.

EDIT: Oh crap. Was that a joke about stopping on the first endian? If so, I just committed a classic geek fail...

I was referring to "little endianness", where the least significant bit is on the left, which makes 10 = 1, whereas in big endian it would be 2 :)

Not quite right. In a little endian system, the least significant byte is the leftmost one (ie, lowest address). The order of bits within a byte is the same regardless of endianness.

So 10 is always 2.

Ah, well I stand corrected, Mr. Hamming :)

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