And I agree, with an UB the original code is undefined and so any optimization is not right nor wrong, simply keep that UB.
But then, why such a long article for a code whose second line is a UB ('p+1' is undefined)?
But then, why such a long article for a code whose second line is a UB ('p+1' is undefined)?
uintptr_t ip = (uintptr_t)(p+1);
Is perfectly defined. What is undefined is converting ip back to a pointer and writing to it, which the original program never does.So now I think it's the first optimization the one that is wrong. If you replace a variable with another, don't you need to keep information of the original variable?
I mean, if a==b and you do *a=1 you can replace it with *b=1, but then you need to keep the information that 'a' was written to, so other optimizations (the third one) don't think it wasn't. Or am I missing something else here?
Edit: sorry for the code block, otherwise the asterisks are removed.Note that ip and iq are integers. If you can't replace integers freely, it makes it really hard to optimize arithmetic.
It constructs a pointer to the "one past the end" element, but that is fine, and the original program never dereferences that pointer. Again: there is no UB in the original program.