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The name seems to imply this project is 3x smaller than K3S[0], does it use less memory, CPU? If this is all about removing external dependencies, I don't think is worth creating an entire new project to avoid installing something like `socat`.

[0]https://k3s.io/

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Technically it is infinite times smaller than k3s or k8s :)

Technically, it would be an undefined number of times easier. n/0 is not infinite.

Technically, we may consider k0s to be the limit of a decreasing sequence of container orchestrators

`k8s, k3s, ... = k{x}s as x -> 0`

in which case we have 8/x -> +inf

Technically, neither the limit or full progression is defined by the information available. The set {k8, k3, k0} may be equally represented as a decreasing series of container orchestrators with reducing prime differences.

I always thought that k3ks was so named because the symbol for 3 looks like a partial symbol for 8, indicating that it's k8s with a bit less.

k3s recently switched to embedded etcd, so if you want something very lightweight out of the box (yet with HA), try Canonical's microk8s it has dqlite support.

k3s still defaults to sqlite. For HA dqlite was dropped in favor of embedded etcd in k3s 1.19.

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