The formula for calculating this is: Q = c_p * d * V * (ΔT). Assuming an isobaric specific heat capacity of 4.18 J/(g K) and a density of 1.00 g/cm^3, heating a liter of water 1.00 K would take 4.18 kJ.

Giving OP's number for the volume of water in the ocean, heating the ocean 0.01 K would be 5.4 * 10^22 J. Assuming 365 days in a year, that's 1.7 * 10^15 W, an order of magnitude less than OPs figure for datacenter power-usage.