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Comment by Znafon | Hacker News Reader

What is a unique, random, sequential prime and how do you actually vote?

Issue 1, 3, 5, 7, 11, 13, 17... up to N for N registered voters. Mix them up and hand out randomly. So let's say you get 5 and I get 7.

To vote, you cast your prime for a candidate, thereby consuming it. No two candidates can share a prime, because their checksums will have a common factor, which is not allowed.

If we both vote for candidate A, his checkproduct is now 35.

If ballots 11, 13 and 17 vote for candidate B, his checkproduct is 2431. Because 2431/5 = 486.2 (non-integer), you can verify that your vote was not counted for B, but it was for A, because 35/5 = 7 (an integer). And because 2431 and 35 don't share any factors, no two votes were counted twice.

Why do you need primes? You could just give everyone a number and publish which numbers voted for each candidate. That is effectively equivalent to what you are doing since each total product can be factored into the primes that voted for it anyways.

In this system you have to trust that the issuing authority never reuses primes. That seeems like a major downside, and something that is hard to overcome with transparency.

People would definitely notice if the checkproduct for two candidates had a nontrivial gcd. Which is almost guaranteed to happen if primes are recycled to a significant degree.

It doesn't work: let's take 4 people and they vote for two choices "1" or "2".

I cheat when I give people their random numbers: A gets 5, B gets 5, C gets 7, D gets 11.

Now they all cast their vote: A -> 1 B -> 1 C -> 2 D -> 2

Let's tally the votes, the result for choice 1 is 5 and the result for choice 2 is 77.

A checks that its vote has been counted 5%5 == 0 so it's good. B checks that its vote has been counted 5%5 == 0 so it's good. C checks that its vote has been counted 77%7 == 0 so it's good. D checks that its vote has been counted 77%11 == 0 so it's good.

For everybody the result appears to be one vote for choice 1, 2 votes for choice 2 and 1 abstention, your scheme does not detect any wrongdoing here.

Of course, you also have to check that your vote was not counted for any of the other candidates.

None of the voters had their vote counted to another candidate here but the result is wrong.

This voting scheme is just broken.

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