A googol-to-one gear ratio [video]
kottke.org
kottke.org
Suppose that:
* The 99 slower gears are massless.
* the fastest gear weighs 10 grams
* The fastest gear is a cylinder of radius of 2cm
* The slowest gear completes 1 rotation every 3 days.
* Relativity only applies when I want it to.
We have: * The fastest gear has an angular velocity of:
w=10^95 radians/second = 10^95 s^-1 //Since radians are unitless
* The fastest gear has a moment of intertia given by:
I=mr^2 / 2 = 10^-2 * 4*10^-4 / 2 kg*m^2
* The fastest gear has a rotational energy of:
E=Iw^2 / 2= 10^-2 * 4*10^-4 / 2 kg*m^2 * 10^190 s^-2 / 2
E = 10^184 kg*m^2*s^-2
* Ignoring all of relativity except E=mc^2, we have
m = E/c^2
m ~ 10^184 kg*m^2*s^-2 / 10 ^ 17 m^2*s^2
m ~ 10^167 kg
* Acknowledging more of relativity now, we have:
Schwarzschild radius = 2Gm / c^2
Schwarzschild radius ~ 10^-12 m^3*kg^-1*s^-2 * 10^167 kg * 10^-17 m^-2*s^2
Schwarzschild radius ~ 10^138 m
Giving us a black hole large enough to fit about 112 googol observable universes.I'm sure that I'm missing some relativistic effects here, but I don't even know how to begin to approach that.
If you want to make these figures a little more reasonable, we could try to spin the slow gear only once in 100 years, in which case you can take about 5 whole powers of 10 off these numbers
*Giving us a black hole with a radius large enough to fit about 112 googol observable universes stacked end-to-end in a line.
~Triple the number of zeros for the number of universes to fit in its 3D volume. 112 x (4/3) x pi followed by 336 zeroes, more or less.
The idea is that there is a certain amount of energy lost as friction in each gear, per turn. If you calculate the gear ratios and how many turns of the earlier gears would be required to make the final gear move, even infinitesimally, the amount of energy lost becomes more than all the energy in the known universe. It's not really about RPMs.
The OP's gears are better laid out to illustrate the concept, and they let you think about what happens with the last gear instead of demonstrating it so... concretely.
There will be finite (but extremely small) compressive/tensile forces that are absorbed in the stretch of the material that the gears and driveline are made out of.
Like stretching a rubber band to double its length takes a force you can feel but stretching it 1/100 of that (or one one millionth or lower) takes effort you don't even notice.
And in this case, the concrete!
Naively you would assume that every rotation of the first gear rotates the last by one googolth. But (I assume) that can't be true in the real world, since that distance is significantly smaller than a planck length.
I have some educated guesses as to how the rotation is actually being "stored" if it's not physically moving the final gear, but I'm probably more ignorant than I think - for example I'm not totally sure I understand what a "planck length" is.
If all of the gears were pre-loaded, such that the slop was "behind" the contacting teeth, then the last gear would turn one googlth of a rotation, with an incomprehensible capacity for torque if it were to encounter any resistance in that very small distance. Being less than a planck length, you might say that the probability of finding the gear's atoms one planck length behind, and one forward, shifts continuously. Of course the atoms are vibrating far greater distances due to ambient heat, but still bonded together.
The frequencies are typically of the order of 10^13 Hz, and the amplitudes are typically of the order of 10^−11 m. A Planck length is about 10^-35.
https://en.wikipedia.org/wiki/Atom_vibrations
Maybe you could say that the gear that shifts approximately one atom vibration (#11) or one planck length (#35) applies as much torque as needed to shift the slower gears behind it, once the force applied becomes greater than the friction resistance, which will happen quite often (about as fast as the atoms are vibrating, if the gears are perfectly tightly meshed) because of the tremendous capacity for torque. There will be higher pressure from the source of the force than from the resistance of the further gears.
As a guess, there should be some slack and elasticity in the last two gears or so, which you could get out if you used enough force. Beyond that, the effective torque is reduced by 100x or 1000x already, which means moving any further gear even by the width of an atom would probably require more torque than the final gear can bear, and either the teeth or some other weak point would fail on the last gear. Of course, even what motion there is (up to failure) would be hard to observe. Moreover, putting this much torque on the end of the structure would also likely torque the entire machine end to end (like twisting a rope) and generally mess things up in uninteresting ways.
Putting all that together, I think an observer would probably say nothing is moving, right until the last gear and/or entire structure fails spectacularly.
It's not - it's a physics problem - it reaches fundamental physical limits of the universe.
Aside, but I'm delighted to learn that one Newton is approximately one apple's worth of force. :)
So you either spin the fast gear an impossible number of times, or spin the slow gear with impossible force.
In fact, I can simulate this in text form with no floating-point or number theory issues at all. Here's the simulation:
> For every 10^100 turns of the first gear, the last gear will move about one full turn.
Better stated, my point is that if the entire assembly is at absolute zero, the quantum fluctuations in the final gear are much greater than the deterministic motion associated with one revolution of the first gear.
I know that would blow the minds of some kids (and adults).
I suspect even if slip between teeth, slack in system, etc... was eliminated you could still get the same effect.
The amount of energy in the system isn't the same thing as the amount of movement, so in a perfectly efficient system (I think) the initial gear would spin faster than the final gear but the final gear would turn with more force (same amount of energy).
That's a big if. I haven't done the math yet, but I'll bet that the outside rim of at least one of the gears would have to be started moving faster than the speed of light. I'm not sure how you would do that.
The gear just before the first gear at light speed would have the outside rim moving at about 100th of the speed of light. It would take quite a bit of energy to do that.
(Others have pointed out that at speeds well before the speed of light, some of the gears would melt. I'm ignoring that.)
This was actually used to construct a cheap mechanism that needed the high g to separate some chemicals to analyse samples. I can't remember the details though.
I'm surprised Oskar van Deventer (YT: OskarPuzzle, https://oskarvandeventer.nl/ ) hasn't done more than 10^9:1 reduction.
I think this calls for 10^10^2 reduction using a series of cycloidal drives (34x 1000:1 should do it just fine)
I am curious how this ratio is calculated though, I didn't drill into the relative ratios.. If anyone has a link I would love to see!
If you chain 100 such reductions, you get 10^100 to one reduction.
For example: If 1 gear(cog?) is 1/1000 of a cm out, would that not effect the ratio over this 'distance' ?
Edit: I might just sound like an idiot right now, but when we get down (or up) to these numbers, i can't help but feel manufacturing numbers play a bigger role
Even if you managed to make a contraption that turned one electron into one rotation of the first wheel, and you fed the entire universe to your contraption... you’re coming up a few dozens order of magnitude short to make that full turn :^)
> where are you going to get that much energy to turn them so fast?
(I know you did - but any chance to introduce Eddington’s number is fun)
But that just isn't going to be tractable.
Why not put it in a dark room before starting up
If you imagine a relativistic spinning disk anyway, then it gets interesting because due to length contraction, the circumference changes relative to the diameter. I'm not up to the math, but it seems like it might change the effective gear ratio depending on your perspective and the closeness of the speed to C.