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> It seems very unlikely that 2 would occur because mining power approaches the brute force limits of SHA-256.

Can you elaborate on this a bit more? I'm not following what you mean by the "mining power approaches the brute force limits of SHA-256."

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If Bitcoin mining power continues to increase exponentially, it will eventually get to the point that it will brute force the output space of the SHA-256. This won't actually happen because 2^256 is a very^256 big number.

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