> For perfect reflection, no.

That's not true, it wouldn't conserve energy. The kinetic energy of the object that's hit changes, so the light must lose or gain energy. I think for a reflection this must be because of a red- or blueshift.

> What you're referring to is light absorption, which is a different effect that raises the temperature of the target object and red-shifts the incoming photon.

Absorption usually means a whole photon is absorbed, not redshifted. A lower energy photon can sometimes be emitted after absorption (however the direction and phase relation with the previous photon are lost)