Hacker News Reader

After you calc X^Y, when you will calc X^(Y+1), doesn't it worth to calc using the previous result (X^Y)*X instead of another power X^(Y+1) ?

View on HN

You will find here that the run-time is swamped by the digit breakdown and summing, so that exponentiation versus accumulated product doesn't make a palpable difference.

Reply on news.ycombinator.com