Ek=mc^2/√(1−(v/c)^2)−mc^2
For v<<c you have significant discrepancies on the energy required to accelerate to a specific speed with regard to mass. I.E. Newton: Ek=(mv^2)/2
As v->c it does not matter as much, the lorentz factor is much more significant, the mass operates just as a base multiplier and sum factor.
As v->c, x->0 where Ek~1/x, i.e. tending to infinity with a division by zero when v=c.
In conclusion, the speed is the relevant factor instead of mass when near speed of light, regardless of the object being an electron or the mount Everest.
Of course, assuming the equation holds ;-)