Life lessons from differential equations (2015)
johndcook.com
johndcook.com
0 is often a trivial solution to many PDEs, but it is of little analytical value, so it is often discarded. In the same sense death is a trivial of many life problems: Dying would solve most (all?) problems in life, but it is not a solution you would typically consider :)
My best guess at the current moment is to extend the universe's life but the inevitable heat death if correct throws a wrench in that.
However if there is a way to create continuity from discreteness, and we can simulate our universe, we may be able to run a child universe to completion before our own universe dies. And if the same thing happens in that child, we will have had an infinite number of universes live and die in the finite life of our own universe. If that isn't a full life for a universe, I don't know what is...
This already may be happening if black holes birth and contain universes.
If you're trying to figure out "what the universe would like", you're going to be searching until the heat death of the universe.
> However if there is a way to create continuity from discreteness, and we can simulate our universe, we may be able to run a child universe to completion before our own universe dies.
This is ontologically unworkable. The sooner you accept that nothing will last forever, the sooner you can get to living your life and enjoying the things that are here right now.
(The fact that φ is zero outside a finite interval mean the “uv” term from integration by parts is zero.)
Can anyone elaborate on this? I'm not too sure how this trick works.
This is the wikipedia page on integration by parts: https://en.wikipedia.org/wiki/Integration_by_parts
He's setting u = phi(x), v = f(x).
Since he's integrating on the real line, a = -infinity, b = +infinity, so on the right hand side for "uv" you'd have u(+inf)v(+inf) - u(-inf)v(-inf) - and since u (which is phi) is 0 outside of a finite interval, you know these terms are 0.
[You obviously can't evaluate functions at +-inf, and you have to take limits to evaluate u(x)v(x) for an improper integral, but you can see the result is the same if u(x) is zero outside of a finite interval]
thankfully the use of infinite series can help a lot in such situations
Don't confuse "exact solution" with "solution" (unqualified). There is no problem that has no solution.
I stopped reading there.
But many people call only an object that exists a solution and has no solution just means no such object exist.
If you take ill posed problems - the barber that shaves everyone that doesn’t shave themselves. Then you are no longer able to answer with true/false so in the limited context there is indeed no solution.
It’s not a good solution, but it is one nonetheless!
The same can be said about taxes. They were the solution for problems like giving people access to education and healthcare.