No. C++ const just means "I won't mutate this object" (through the const pointer). It doesn't mean that somebody else won't mutate the some object (through their non-const pointer to the same object).
struct X {
const int i{123};
const int j;
X(int j_) : j{j_} {}
};
// non-const object; x.i == 123; x.j == 111
X x{111};
x.i = 222; // compilation error
x.j = 333; // compilation error struct X {
X(Y val) : y_{val} {}
// Can be called on const and non-const X objects
const Y& y() const { return y_; }
// Can only be called on non-const X objects
Y& y() { return y_; }
private:
Y y_;
};
void f(X& x) { x.y() = 222; }
void g(const X& x) { x.y() = 222); }
const X x{123}; // x.y() == 123
x.y() = 222; // compilation error
f(x); // compilation error (f's parm is non-const)
g(x); // compilation error (can't assign to const ref)
// Cannot take non-const ref or ptr of x
X& xr{x}; // compilation error
X* xp{&x}; // compilation error
X& xr{const_cast<X&>(x)};
X* xp(const_cast<X*>(&x)};So, a const value cannot be mutated locally or globally. So if you make something const and expose it, it cannot be changed.