Visualising Electromagnetic Fields
lukesturgeon.co.uk
lukesturgeon.co.uk
I found it interesting but not interesting enough to pursue a career in power engineering :-).
Stanford Seminar: 42 years of Phenomenological AR for Natural/Reality/Direct User-Interfaces https://www.youtube.com/watch?v=6IpBVC-p3iU
Example in video https://youtu.be/6IpBVC-p3iU?t=2436
https://en.wikipedia.org/wiki/Riemann_sum
I think it forms a nice bridge from univariate calculus to visualizing the vector fields.
You probably have seen images like this, you just might not have realized. Many of the most beautiful astronomy photographs are actually captured in different spectrums. If you've ever seen a "thermal image" that is also non-visible photons.
Some examples:
https://asd.gsfc.nasa.gov/blueshift/wp-content/uploads/2013/...
https://smd-prod.s3.amazonaws.com/science-red/s3fs-public/th...
http://www.greenbuildingadvisor.com/sites/default/files/Ther...
Of course you have, it's called an x-ray.
That's not right - visible light is sort of a "midrange" photon energy that's exceeded by ultraviolet, x-rays and gamma rays and preceded by infrared, microwaves and radio waves. Everyday devices emit at low frequencies, with energies significantly below that of visible light. The higher energies (ultraviolet, xray, gamma) absolutely do have images:
- Ultraviolet [https://en.wikipedia.org/wiki/Ultraviolet_photography#/media...]
- Xray https://en.wikipedia.org/wiki/X-ray#/media/File:Radiograf%C3...
- Gamma https://en.wikipedia.org/wiki/Gamma_ray#/media/File:VACIS_Ga...
Now, the photons with lower energies than visible light form an interesting case. First off there's infrared, which is fairly familiar:
- Infrared https://en.wikipedia.org/wiki/Infrared_photography#/media/Fi...
Now, as the photon energies get lower the wavelengths get longer. This introduces a problem for lower-energy images: when the wavelength is around the size of the aperture, wave-like things will happen involving the aperture. This tends to blur the images, meaning that for longer and longer wavelengths larger and larger cameras are required to achieve the same level of detail. However, these images still exist - but they are rarely taken of everyday things. Note that the imaging you are talking about (to capture the glowing of everyday electronic devices in low frequencies) would have to happen in the microwave and radio bands - because that's around the frequency at which electronics operate. The result is that a reasonably-sized camera would not be able to take a meaningfully sharp image of a router's "glow."
- Microwave https://en.wikipedia.org/wiki/Microwave_imaging#/media/File:...
- Radio Waves http://www.gb.nrao.edu/epo/PageMill_Resources/galaxy.jpg
The radio wave picture depicts a galaxy. Radio imaging setups are usually very large, like this one: http://mstecker.com/pages/astroVLAa15vlad-2c1.htm
the strength of the magnetic field is equal to the (current times the permeability of the medium) divided by (the distance times 2 pi).
magnetic flux is the dot product of the magnetic field and the area vector representing the area through which you want the flux. theres another way to express flux as a ?derivative of voltage? but I can't find a reference and the exact relationship escapes me at the moment.
Just a guess though.
https://hackaday.io/project/4329-wifi-power-mapping
Also see this video which goes over the concept: