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Comment by progval | Hacker News Reader

Shorter version (which actually checks for 0⁰ × 1¹ × 2² × 3³ × 4⁴ × 5⁵):

> [0, 1, 2, 3, 4, 5].map(Math.pow).reduce((a, b) => a * b) === 1000 * 60 * 60 * 24

true

Even shorter version that simply does the calculation from the title of this post:

    5**5*4**4*3**3*2**2*1**1===24*60*60*1000
    
    true

Nice ES7. But if we're not constrained by leaving 5 as a "general" number, then

  864e5 === 24 * 60 * 60 * 1000

This skips the power calculation, which is the entire point!

If we remove some of the cruft on the righthand side, we can save a few bytes:

  864e5;

1 (because it's a bool anyway)

!0 if we actually want the exact value `true` :)

  a=1;for(i=1;i<=5;i++)a*=Math.pow(i,i);a === 1000 * 60 * 60 * 24

  a=1;i=1;while(i++<5)a*=Math.pow(i,i);a === 1000 * 60 * 60 * 24