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Comment by pjmlp | Hacker News Reader

Even better if you make it:

    template<class T>
    constexpr bool is_space(const T & x) {
        return x == ' ' || x == '\n';
    }

Debuggable, type safe and same performance as straight C code.

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Constexpr is not necessary. Only required if you want to ensure that a variable is initialized with a pre-computed value. The compiler will optimize in either case if it can, regardless of the constexpr attribute.

> Only required if you want to ensure that a variable is initialized with a pre-computed value

Yep.

And throw an `inline` in there just to be more likely to end up with something macro-like.

`constexpr` is implicitly `inline`: http://en.cppreference.com/w/cpp/language/inline

orthogonally, templates are also implicitly inline.

Then again, inline does not mean what most people think.

“inline” is more about linkage than about actual inlining. The compiler will in-line regardless of that attribute.

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