For example, in Hebrew the word BRHA can mean several things: "pool", "blessing", "in soft" and "her knee" (no kidding).
For example, in Hebrew the word BRHA can mean several things: "pool", "blessing", "in soft" and "her knee" (no kidding).
EDIT
I found this Hebrew analyzer for Lucene/Solr/Elasticsearch [1] which appears to do stemming or lemmatization. Potentially you could use the output of the analyzer as the input to word2vec.
> But maybe lemmatization would be better than stemming
You're right, I'm using "stemming" and "lemmatization" interchangeably where I shouldn't. What I mean is lemmatization.
> It is also possible that it is an unnecessary step for clustered word vectors for your use case
I don't focus on a specific use case, I'm just trying to find a way to enable full-text search for Hebrew. Searching based on concept similarity is a very cool addition, though, and I do have some use cases in mind for it specifically. But I'm just thinking what a typical cluster would look like, and I imagine 99.9% of it will be different forms of the same handful of base forms. Furthermore, telling Lucene to match based on all these forms will inevitably create a large number of false positives due to the aforementioned abundance of homonyms. So I can see a clear problem here even now. That's why I keep reiterating my original question of whether this system can first be used for lemmatizing and then everything else.
EDIT
I found this paper which may answer your question about lemmatization and word vectors.
http://www.openu.ac.il/iscol2015/downloads/ISCOL2015_submiss...
Thanks for your advice, anyway.
Let's say the user entered three words: A B C. You look up each of them among the vectors and discover that there are three matching vectors for A, four for B and five for C (and for the sake of generality let's assume that there are more words than just 3 in the input, so it's impractical to test every subset of these words for co-occurrence). How do you jointly select the correct vector for each of the words?
Let x1 be the number of vectors matching A, x2 the number of vectors matching B, etc, till xn. Let c1..cn be a particular selection of vectors. Now my main assumption here is that in order to determine which of these vectors are most often encountered together in the same context [1], our goal is to find j that maximizes sum_{i from 1 to n, i!=j}[d_i], where d_i=(c_j dot c_i) if the dot product is nonnegative, otherwise d_i=0. I'm not sure it's true primarily because I don't know if by summing up these dot products we add apples to apples or apples to oranges.
Then in order to find the best selection of vectors c1..cn we can iterate on every vector v_k matching A and dot v_k with every vector matching B, then pick the maximum m2 (or 0 if it's negative); dot v_k with every vector matching C, then pick the maximum m3; etc. Thus, for k'th iteration we obtain the selection of vectors that maximizes M_1k=sum_i[m_i]. After we're done with all c1 iterations, we pick the best such selection M1=max_k[M_1k]. This is all done in O(x1(x2+x3+...xn)) time.
Next, we repeat the above process for all x2 vectors matching B and obtain M2, etc, etc. Ultimately, we pick the selection of vectors that produced the highest M_t across all choices of t. Overall, we get O((sum_i[xi])^2), which seems fast enough. What do you think?
[1] One obvious problem is this limits the number of contexts we match against to just one.
But it seems it's been solved, too: https://github.com/sbos/AdaGram.jl